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King_Snake

  • 2 years ago

How would i sketch y = Ix + 1I

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  1. Cooner
    • 2 years ago
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    Start by drawing a graph with x values going from -5 to 5 and y values going from 0 upwards. Then put values in for x between -5 and 5. so lets start with x=0. y(0)=abs(0+1)=1 where abs means absolute. Absolute value means y can not be negative for this function(which is why we plot the graph going from 0 up for 'y' values). eg. x=-5 y(-5)=abs(-5+1)=abs(-4)=4.

  2. manishsatywali
    • 2 years ago
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    do u knw the sketching of graph y =modx

  3. Cooner
    • 2 years ago
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    mod?

  4. matricked
    • 2 years ago
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    draw the graph of y=|x| first and then shift the vertex to -1,0 graph of y=|x| is V sahped symmetrical about y-axis and inclined at 45 wrt x-axis

  5. manishsatywali
    • 2 years ago
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    if u know the graph of modulus x the apply curve transformation by shift the vertex to -1,0

  6. zzr0ck3r
    • 2 years ago
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    lol omg mod to graph abs(x)???????? ....graph abs(x) then move it to the left 1

  7. zzr0ck3r
    • 2 years ago
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    |dw:1359616056144:dw|

  8. manishsatywali
    • 2 years ago
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    |dw:1359615937866:dw|

  9. manishsatywali
    • 2 years ago
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    for modulus x+1 graph

  10. manishsatywali
    • 2 years ago
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    bottom of the above diagram

  11. manishsatywali
    • 2 years ago
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    here u have shift the origin of modulus x from 0 to -1

  12. manishsatywali
    • 2 years ago
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    |dw:1359616239891:dw|

  13. zzr0ck3r
    • 2 years ago
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    do you think that someone that does not know how to deal with a shift would know anything about modulo?

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