How would i sketch y = Ix + 1I

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How would i sketch y = Ix + 1I

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Start by drawing a graph with x values going from -5 to 5 and y values going from 0 upwards. Then put values in for x between -5 and 5. so lets start with x=0. y(0)=abs(0+1)=1 where abs means absolute. Absolute value means y can not be negative for this function(which is why we plot the graph going from 0 up for 'y' values). eg. x=-5 y(-5)=abs(-5+1)=abs(-4)=4.
do u knw the sketching of graph y =modx
mod?

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Other answers:

draw the graph of y=|x| first and then shift the vertex to -1,0 graph of y=|x| is V sahped symmetrical about y-axis and inclined at 45 wrt x-axis
if u know the graph of modulus x the apply curve transformation by shift the vertex to -1,0
lol omg mod to graph abs(x)???????? ....graph abs(x) then move it to the left 1
|dw:1359616056144:dw|
|dw:1359615937866:dw|
for modulus x+1 graph
bottom of the above diagram
here u have shift the origin of modulus x from 0 to -1
|dw:1359616239891:dw|
do you think that someone that does not know how to deal with a shift would know anything about modulo?

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