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King_Snake
How would i sketch y = Ix + 1I
Start by drawing a graph with x values going from -5 to 5 and y values going from 0 upwards. Then put values in for x between -5 and 5. so lets start with x=0. y(0)=abs(0+1)=1 where abs means absolute. Absolute value means y can not be negative for this function(which is why we plot the graph going from 0 up for 'y' values). eg. x=-5 y(-5)=abs(-5+1)=abs(-4)=4.
do u knw the sketching of graph y =modx
draw the graph of y=|x| first and then shift the vertex to -1,0 graph of y=|x| is V sahped symmetrical about y-axis and inclined at 45 wrt x-axis
if u know the graph of modulus x the apply curve transformation by shift the vertex to -1,0
lol omg mod to graph abs(x)???????? ....graph abs(x) then move it to the left 1
|dw:1359615937866:dw|
for modulus x+1 graph
bottom of the above diagram
here u have shift the origin of modulus x from 0 to -1
|dw:1359616239891:dw|
do you think that someone that does not know how to deal with a shift would know anything about modulo?