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Cooner
 2 years ago
Best ResponseYou've already chosen the best response.0Start by drawing a graph with x values going from 5 to 5 and y values going from 0 upwards. Then put values in for x between 5 and 5. so lets start with x=0. y(0)=abs(0+1)=1 where abs means absolute. Absolute value means y can not be negative for this function(which is why we plot the graph going from 0 up for 'y' values). eg. x=5 y(5)=abs(5+1)=abs(4)=4.

manishsatywali
 2 years ago
Best ResponseYou've already chosen the best response.0do u knw the sketching of graph y =modx

matricked
 2 years ago
Best ResponseYou've already chosen the best response.0draw the graph of y=x first and then shift the vertex to 1,0 graph of y=x is V sahped symmetrical about yaxis and inclined at 45 wrt xaxis

manishsatywali
 2 years ago
Best ResponseYou've already chosen the best response.0if u know the graph of modulus x the apply curve transformation by shift the vertex to 1,0

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0lol omg mod to graph abs(x)???????? ....graph abs(x) then move it to the left 1

manishsatywali
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1359615937866:dw

manishsatywali
 2 years ago
Best ResponseYou've already chosen the best response.0for modulus x+1 graph

manishsatywali
 2 years ago
Best ResponseYou've already chosen the best response.0bottom of the above diagram

manishsatywali
 2 years ago
Best ResponseYou've already chosen the best response.0here u have shift the origin of modulus x from 0 to 1

manishsatywali
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1359616239891:dw

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0do you think that someone that does not know how to deal with a shift would know anything about modulo?
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