anonymous
  • anonymous
Find an equation of the circle that satisfies the given conditions. Center at the origin; passes through (3, 6)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
suppose the equation is \[x^2+y^2+2gx+2fy+c=0\]
anonymous
  • anonymous
equation of circle (x-a)^2 + (y-b)^2 = r put a =b = 0
anonymous
  • anonymous
where the center is (g,x)

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anonymous
  • anonymous
|dw:1359617100905:dw|
anonymous
  • anonymous
as it is in origin , g=0,x=0..so 3^2+6^2=c
anonymous
  • anonymous
srry instead of it should be r^2
anonymous
  • anonymous
c=45, the equation is \[x^2+y^2=45\]
anonymous
  • anonymous
instead of r it should be r^2
anonymous
  • anonymous
|dw:1359617230658:dw|

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