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ehamer

  • 3 years ago

Find an equation of the circle that satisfies the given conditions. Center at the origin; passes through (3, 6)

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  1. sritama
    • 3 years ago
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    suppose the equation is \[x^2+y^2+2gx+2fy+c=0\]

  2. manishsatywali
    • 3 years ago
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    equation of circle (x-a)^2 + (y-b)^2 = r put a =b = 0

  3. sritama
    • 3 years ago
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    where the center is (g,x)

  4. manishsatywali
    • 3 years ago
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    |dw:1359617100905:dw|

  5. sritama
    • 3 years ago
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    as it is in origin , g=0,x=0..so 3^2+6^2=c

  6. manishsatywali
    • 3 years ago
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    srry instead of it should be r^2

  7. sritama
    • 3 years ago
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    c=45, the equation is \[x^2+y^2=45\]

  8. manishsatywali
    • 3 years ago
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    instead of r it should be r^2

  9. manishsatywali
    • 3 years ago
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    |dw:1359617230658:dw|

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