ehamer
Find an equation of the circle that satisfies the given conditions.
Center at the origin; passes through (3, 6)



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sritama
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suppose the equation is \[x^2+y^2+2gx+2fy+c=0\]

manishsatywali
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equation of circle (xa)^2 + (yb)^2 = r put a =b = 0

sritama
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where the center is (g,x)

manishsatywali
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dw:1359617100905:dw

sritama
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as it is in origin , g=0,x=0..so 3^2+6^2=c

manishsatywali
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srry instead of it should be r^2

sritama
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c=45,
the equation is \[x^2+y^2=45\]

manishsatywali
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instead of r it should be r^2

manishsatywali
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dw:1359617230658:dw