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ParthKohli

  • 3 years ago

What'd the last digit of the expansion of \(2^{12n} - 6^{4n}\) be? I know that it is \(0\) by trying out \(n = 0\), but a more formalized approach would be...?

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  1. ParthKohli
    • 3 years ago
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    \[2^{12n} - 2^{4n}3^{4n}\]Then\[2^{4n}(2^{8n} - 3^{4n})\]What next?

  2. ParthKohli
    • 3 years ago
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    Modulo 10?

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