(x/x-3)^2-2(x/x-3)-15=0

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(x/x-3)^2-2(x/x-3)-15=0

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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If you write it in proper math notation:\[\left( \frac{ x }{ x-3 } \right)^2-2\left( \frac{ x }{ x-3 } \right)-15=0\]you see that it looks like a quadratic equation... So set p=x/(x-3) to get:\[p^2-2p-15=0\] Solve for p. Then remember that p=x/(x-3) and solve that for x!
Yeah whenever I do that I get x=5 and x=-3 but I don't know how to go from there
But you get p=5 and p=-3, so you still have to do solve\[\frac{ x }{ x-3 }=5\]and\[\frac{ x }{ x-3 }=-3\]I will get you started with these:\[\frac{ x }{ x-3 }=\frac{ 5 }{ 1 }\]You see two equal fractions. In general this can be dealt with the following way:\[\frac{ a }{ b }=\frac{ c }{ d } \Leftrightarrow ad=bc\]So do the multiplications and then solve for x.

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Other answers:

X=9/2 and x= 5/2
Hold on, let me do it myself... ;)
I've found different solutions, I'm afraid...\[x \cdot 1=5 \cdot (x-3) \Leftrightarrow x=5x-15 \Leftrightarrow 4x=15\]so x=15/4. Maybe you forgot to multiply 5 and -3?
Second one: x*1=-3*(x-3), so x=-3x+9, 4x=9, x=9/4 So I've got 15/4 and 9/4
ok let me see how you did it lol
I just did...!
Do you understand what went wrong?
No, I don't see how you get 5/1
oh wait! I get it nvm!
Welcome!
Thank you so much! I was so lost! lol
Next time, you won't be!

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