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ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1If you write it in proper math notation:\[\left( \frac{ x }{ x3 } \right)^22\left( \frac{ x }{ x3 } \right)15=0\]you see that it looks like a quadratic equation... So set p=x/(x3) to get:\[p^22p15=0\] Solve for p. Then remember that p=x/(x3) and solve that for x!

cuban_mind
 one year ago
Best ResponseYou've already chosen the best response.0Yeah whenever I do that I get x=5 and x=3 but I don't know how to go from there

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1But you get p=5 and p=3, so you still have to do solve\[\frac{ x }{ x3 }=5\]and\[\frac{ x }{ x3 }=3\]I will get you started with these:\[\frac{ x }{ x3 }=\frac{ 5 }{ 1 }\]You see two equal fractions. In general this can be dealt with the following way:\[\frac{ a }{ b }=\frac{ c }{ d } \Leftrightarrow ad=bc\]So do the multiplications and then solve for x.

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1Hold on, let me do it myself... ;)

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1I've found different solutions, I'm afraid...\[x \cdot 1=5 \cdot (x3) \Leftrightarrow x=5x15 \Leftrightarrow 4x=15\]so x=15/4. Maybe you forgot to multiply 5 and 3?

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1Second one: x*1=3*(x3), so x=3x+9, 4x=9, x=9/4 So I've got 15/4 and 9/4

cuban_mind
 one year ago
Best ResponseYou've already chosen the best response.0ok let me see how you did it lol

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1Do you understand what went wrong?

cuban_mind
 one year ago
Best ResponseYou've already chosen the best response.0No, I don't see how you get 5/1

cuban_mind
 one year ago
Best ResponseYou've already chosen the best response.0oh wait! I get it nvm!

cuban_mind
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much! I was so lost! lol

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1Next time, you won't be!
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