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anonymous
 3 years ago
(x/x3)^22(x/x3)15=0
anonymous
 3 years ago
(x/x3)^22(x/x3)15=0

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you write it in proper math notation:\[\left( \frac{ x }{ x3 } \right)^22\left( \frac{ x }{ x3 } \right)15=0\]you see that it looks like a quadratic equation... So set p=x/(x3) to get:\[p^22p15=0\] Solve for p. Then remember that p=x/(x3) and solve that for x!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah whenever I do that I get x=5 and x=3 but I don't know how to go from there

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But you get p=5 and p=3, so you still have to do solve\[\frac{ x }{ x3 }=5\]and\[\frac{ x }{ x3 }=3\]I will get you started with these:\[\frac{ x }{ x3 }=\frac{ 5 }{ 1 }\]You see two equal fractions. In general this can be dealt with the following way:\[\frac{ a }{ b }=\frac{ c }{ d } \Leftrightarrow ad=bc\]So do the multiplications and then solve for x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hold on, let me do it myself... ;)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I've found different solutions, I'm afraid...\[x \cdot 1=5 \cdot (x3) \Leftrightarrow x=5x15 \Leftrightarrow 4x=15\]so x=15/4. Maybe you forgot to multiply 5 and 3?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Second one: x*1=3*(x3), so x=3x+9, 4x=9, x=9/4 So I've got 15/4 and 9/4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok let me see how you did it lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you understand what went wrong?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, I don't see how you get 5/1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh wait! I get it nvm!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you so much! I was so lost! lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Next time, you won't be!
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