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sue101 Group Title

What is the product in simplest form? State any restrictions on the variable.

  • one year ago
  • one year ago

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  1. sue101 Group Title
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    (4a^5/7b^4) * (2b^2/2a^4)

    • one year ago
  2. sue101 Group Title
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    @Hero

    • one year ago
  3. Hero Group Title
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    Rewrite like this: \[\frac{4a^5 \dot\ 2b^2}{2a^4 \dot\ 7b^4}\]

    • one year ago
  4. sue101 Group Title
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    ok and then?

    • one year ago
  5. sue101 Group Title
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    do i just multiply accross?

    • one year ago
  6. Hero Group Title
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    Or you can work with each separately by re-writing like this: \[\frac{4}{2} \dot\ \frac{a^5}{a^4} \dot\ \frac{2}{7} \dot\ \frac{b^2}{b^4}\]

    • one year ago
  7. sue101 Group Title
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    so it would be 8ab^7??

    • one year ago
  8. sue101 Group Title
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    for the top part?

    • one year ago
  9. Hero Group Title
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    No

    • one year ago
  10. sue101 Group Title
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    wow thats confusing o.O

    • one year ago
  11. Hero Group Title
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    You already know how to reduce the numerical fractions.

    • one year ago
  12. Hero Group Title
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    You know that 4/2 = 2. You also know that 2/7 is already in simplest form and cannot be reduced any further

    • one year ago
  13. sue101 Group Title
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    mhk

    • one year ago
  14. Hero Group Title
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    So for the numbers, you are just left with \[2 \times \frac{2}{7} = \frac{4}{7}\]

    • one year ago
  15. Hero Group Title
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    For the variables, you have to use this rule: \[\frac{a^y}{a^x} = a^{y - x}, y > x\] \[\frac{b^x}{b^y} = \frac{1}{b^{y-x}}, x<y\]

    • one year ago
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    So \[\frac{a^5}{a^4} = a^{5 - 4} = a^1 = a\] \[\frac{b^2}{b^4} = \frac{1}{b^{4-2}} = \frac{1}{b^2}\]

    • one year ago
  17. sue101 Group Title
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    thes are my multiple choice answers: 4a^9/7b^^6 4a/7b^2 7b^2/4a 4/7a^9b^6

    • one year ago
  18. Hero Group Title
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    \[\frac{4}{7} \times a \times \frac{1}{b^2} = \frac{4a}{7b^2}\]

    • one year ago
  19. sue101 Group Title
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    alirght so B? Thanks! <3

    • one year ago
  20. Hero Group Title
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    You should learn how to do these on your own.

    • one year ago
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