angelwings996
  • angelwings996
Algebra 2 help please!? Simplify the sum. State any restrictions on the variables.
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

angelwings996
  • angelwings996
1 Attachment
Hero
  • Hero
Hint: Multiply the first fraction by (x - 3)/(x-3)
angelwings996
  • angelwings996
so would it become \[\frac{ x ^{2} + 5x + 6 }{ x ^{2} - 9 }\] @Hero

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

phi
  • phi
are you posting one of the multiple choices ?
angelwings996
  • angelwings996
This isn't a multiple choice problem
phi
  • phi
you have the wrong sign on 5x
Hero
  • Hero
Actually the numerator should be x^2 - 5x + 6
angelwings996
  • angelwings996
Okay, then what would I do?
phi
  • phi
once you have a common denominator, you can combine the tops
mathstudent55
  • mathstudent55
Since you are adding fractions, you need a common denominator. The denominator of the left fraction is simply x + 3. You need to factor the denominator of the right fraction. x^2 - 9 = (x + 3)(x - 3)
mathstudent55
  • mathstudent55
Since the right denominator has factors (x + 3)(x - 3) and the left fraction only has (x + 3), you need to multiply the numerator and denominator of the left fraction by (x - 3).
angelwings996
  • angelwings996
Okay, I get you so far
mathstudent55
  • mathstudent55
Then multiply out the numerator of the left fraction (x + 3)(x - 2)
angelwings996
  • angelwings996
Okay I did that
mathstudent55
  • mathstudent55
|dw:1359654823726:dw|
mathstudent55
  • mathstudent55
|dw:1359654885990:dw|
angelwings996
  • angelwings996
What did you do here?
mathstudent55
  • mathstudent55
Since both fractions now have the same denominator, you can write them as a single fraction over the common denominator. Now combine like terms in the numerator.
angelwings996
  • angelwings996
Ohh okay
mathstudent55
  • mathstudent55
I multiplied out the left numerator and I added the right numerator, and set the whole thing over the common denominator.
mathstudent55
  • mathstudent55
Now combine like terms on the numerator.
mathstudent55
  • mathstudent55
Then try factoring the numerator.
angelwings996
  • angelwings996
When I combine like terms I got \[\frac{ x ^{2} + 11x - 6 }{ (x+3)(x-3) }\]
mathstudent55
  • mathstudent55
Correct. The last step is to try to factor the numerator to see if you can simplify the fraction.
angelwings996
  • angelwings996
I can't figure out how to factro this, nothing I can find will come up with both 11 and 6
mathstudent55
  • mathstudent55
This kind of factoring involves finding two numbers that multiply to -6 and add to 11. There aren't any, so it can't be factored, and the addition is finished.
angelwings996
  • angelwings996
Okay, What would the restrictions be then ? @mathstudent55
angelwings996
  • angelwings996
Would the answer be with the denominator factored or can I put x^2 - 9 ?
mathstudent55
  • mathstudent55
The restrictions are any values of x that would make the denominator zero. Since the denominator is x^2 - 9 which you know factors into (x + 3)(x - 3), set x + 3 = 0 and solve for x and set x - 3 = 0 and solve for x. Those two x values are the restrictions.
angelwings996
  • angelwings996
Okay thank you..so the answer woould be \[\frac{ x ^{2} + 11x - 6 }{ (x + 3)(x - 3) } ; x \neq -3, 3\] @mathstudent55
angelwings996
  • angelwings996
Or would I put x^2 - 9 as the denominator ?
mathstudent55
  • mathstudent55
You can leave the denominator factored. It's perfectly acceptable. It's also fine to multiply it out. Either way is good.
angelwings996
  • angelwings996
Okay, thank you so much for your help ! (:

Looking for something else?

Not the answer you are looking for? Search for more explanations.