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dainel40
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There are two forces on the 2.61 kg box in the overhead view of the figure but only one is shown. For F1 = 13.2 N, a = 14.4 m/s2, and θ = 28.1°, find the second force (a) in unitvector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
 one year ago
 one year ago
dainel40 Group Title
There are two forces on the 2.61 kg box in the overhead view of the figure but only one is shown. For F1 = 13.2 N, a = 14.4 m/s2, and θ = 28.1°, find the second force (a) in unitvector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
 one year ago
 one year ago

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azolotor Group TitleBest ResponseYou've already chosen the best response.0
\[a \sin \theta = ycomponent\]\[a \cos \theta = xcomponent\] \[theta\] from the +x axis just add 180 to \[theta\] so you get 28.1+180=208.1 so you have the direction, you already know the magnitude and you know the magnitude already as it is given. The first part is a little right triangle trigonometry so make sure you are up on that.
 one year ago

dainel40 Group TitleBest ResponseYou've already chosen the best response.0
ok thanks
 one year ago
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