anonymous
  • anonymous
Solve the system by using elimination or elimination with multiplication. 3x + 4y = -2 and 2x - 3y = 10
Algebra
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Is it together or are they two separate problems?
anonymous
  • anonymous
They are together.
phi
  • phi
3x + 4y = -2 2x - 3y = 10 one way is to multiply the top equation (that means every term BOTH sides) by -2 and multiply the 2nd equation by +3 what do you get for the 2 new equations ?

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anonymous
  • anonymous
Is the new equations -6x+-8y=4 and 6x+9y=30? Or did I do something wrong?
phi
  • phi
close . redo the 2nd equation.
anonymous
  • anonymous
Do you change the + to a -?
phi
  • phi
3*(2x-3y)= 3*10 6x -9y = 30
phi
  • phi
now add the 2 equations -6x+ -8y=4 6x+ -9y=30
anonymous
  • anonymous
Like this? 6x-9y=30 or is it like this? 6x-(-9y)=30?
phi
  • phi
are you asking what you get when you multiply the 2nd equation by 3 ? 2x + -3y = 10 3 times each term: 3*2x + 3* -3y = 3*10 there is only 1 minus sign, and it stays you get 6x -9y = 30
anonymous
  • anonymous
Oh, okay. I get it. Sorry, I got kicked off for a few minutes.
anonymous
  • anonymous
Then, you add them and the 6's cancel out right? Then you would have 0x+17y=34 right or would it be a -?
anonymous
  • anonymous
Okay, thank you so much for your help! I finally figured out the answer.
phi
  • phi
now add the 2 equations -6x+ -8y=4 6x+ -9y=30

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