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it is a well known limit
\[\lim_{x\to 0}\frac{\sin(x)}{x}=1\]

1) lim x-> 2 (x-5/x^2 + 4)
2) lim x-> 3 (x^2 - x - 6/x - 3)
3) lim h-> 0 ((2 + h)^2 - 4/h)

1) replace \(x\) by 2

ok

2) factor as
\[\frac{(x-3)(x+2)}{x-3}=x+2\] then replace \(x\) by 3

okay

ok

for number 4) its this one lim t-> -2 (1/2 + 1/t over 2 + t)

and 5) lim x->4 + sqrt(16 - x^2)

ok

okay thanks alot :)