littile question on statistics, picture below

- anonymous

littile question on statistics, picture below

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- schrodinger

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- anonymous

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- anonymous

can you explain that?

- anonymous

its about statistics

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## More answers

- anonymous

yes let me see how I want to explain it

- JamesJ

The second part is asking you for the value of R^2. Sounds familiar?

- anonymous

ow ` I just have to square it ?

- anonymous

what if it asks The Buick Regal has a horsepower of 127. What is the predicted mileage for the Buick Regal?

- anonymous

i have to plug 127 into function?

- JamesJ

yes

- anonymous

what about this one Predicting the value of a response variable for an individual whose x-value is out of our range of data is called

- JamesJ

Then you can still use the regression line to derive an predicted value for y, given the x. However, it is likely to be less reliable for an x outside the range of x in the original sample, particularly if it is a long way outside of that range.

- anonymous

so how should I answer this question ?

- JamesJ

I'm guessing just use your regression line if it asking you for an actual predicted y value

- anonymous

Im sorry, I dont get it

- anonymous

is it going to be extrapolation

- JamesJ

Yes

- anonymous

I think it asking for definition of extrapolation

- JamesJ

Well, that's why you have a textbook. Look it up.

- anonymous

so, my last question is What is the residual for the Chevy Malibu?

- JamesJ

Residual is the difference between the predicted and actual value. So calculate the predicted value and compare it to the actual.

- anonymous

So, I have to plug 251 and 28 into fuction?

- JamesJ

No. You are predicting one variable in terms of the other, using the regression line. You are predicting the value of y, given x. You are predicting the value of mileage as a function of horsepower.
That gives you the predicted value of mileage.
The residual is then the difference between this predicted number and the actual mileage.
These are fundamental concepts. I recommend you go back and re-read your lecture notes and/or the chapter in your text book to make sure you have this straight.

- anonymous

ok , got it thanks

- anonymous

I got the answer for that -2.1380

- anonymous

could you expalin this one?

- anonymous

Suppose we had instead measured mileage in kilometers per liter (1 m/g = 0.425 km/l). What would be the value of the correlation between X and Y?

- phi

to change from mile per gallon to km per liter you would multiply each mileage value by a conversion factor (a fixed number).
call that number a. If you plug in that factor everywhere into your formula how does it change the final correlation ?

- anonymous

satys same?

- anonymous

is it 0.8651 ?

- phi

yes, it stays the same. But you can prove it to yourself.

- anonymous

but when I enter the answer 0.8651 . it says , it's wrong

- anonymous

now ,its right , thank you very much

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