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yashar806

  • one year ago

littile question on statistics, picture below

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  1. yashar806
    • one year ago
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  2. yashar806
    • one year ago
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    can you explain that?

  3. yashar806
    • one year ago
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    its about statistics

  4. JuanitaM
    • one year ago
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    yes let me see how I want to explain it

  5. JamesJ
    • one year ago
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    The second part is asking you for the value of R^2. Sounds familiar?

  6. yashar806
    • one year ago
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    ow ` I just have to square it ?

  7. yashar806
    • one year ago
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    what if it asks The Buick Regal has a horsepower of 127. What is the predicted mileage for the Buick Regal?

  8. yashar806
    • one year ago
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    i have to plug 127 into function?

  9. JamesJ
    • one year ago
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    yes

  10. yashar806
    • one year ago
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    what about this one Predicting the value of a response variable for an individual whose x-value is out of our range of data is called

  11. JamesJ
    • one year ago
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    Then you can still use the regression line to derive an predicted value for y, given the x. However, it is likely to be less reliable for an x outside the range of x in the original sample, particularly if it is a long way outside of that range.

  12. yashar806
    • one year ago
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    so how should I answer this question ?

  13. JamesJ
    • one year ago
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    I'm guessing just use your regression line if it asking you for an actual predicted y value

  14. yashar806
    • one year ago
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    Im sorry, I dont get it

  15. yashar806
    • one year ago
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    is it going to be extrapolation

  16. JamesJ
    • one year ago
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    Yes

  17. yashar806
    • one year ago
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    I think it asking for definition of extrapolation

  18. JamesJ
    • one year ago
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    Well, that's why you have a textbook. Look it up.

  19. yashar806
    • one year ago
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    so, my last question is What is the residual for the Chevy Malibu?

  20. JamesJ
    • one year ago
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    Residual is the difference between the predicted and actual value. So calculate the predicted value and compare it to the actual.

  21. yashar806
    • one year ago
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    So, I have to plug 251 and 28 into fuction?

  22. JamesJ
    • one year ago
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    No. You are predicting one variable in terms of the other, using the regression line. You are predicting the value of y, given x. You are predicting the value of mileage as a function of horsepower. That gives you the predicted value of mileage. The residual is then the difference between this predicted number and the actual mileage. These are fundamental concepts. I recommend you go back and re-read your lecture notes and/or the chapter in your text book to make sure you have this straight.

  23. yashar806
    • one year ago
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    ok , got it thanks

  24. yashar806
    • one year ago
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    I got the answer for that -2.1380

  25. yashar806
    • one year ago
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    could you expalin this one?

  26. yashar806
    • one year ago
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    Suppose we had instead measured mileage in kilometers per liter (1 m/g = 0.425 km/l). What would be the value of the correlation between X and Y?

  27. phi
    • one year ago
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    to change from mile per gallon to km per liter you would multiply each mileage value by a conversion factor (a fixed number). call that number a. If you plug in that factor everywhere into your formula how does it change the final correlation ?

  28. yashar806
    • one year ago
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    satys same?

  29. yashar806
    • one year ago
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    is it 0.8651 ?

  30. phi
    • one year ago
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    yes, it stays the same. But you can prove it to yourself.

  31. yashar806
    • one year ago
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    but when I enter the answer 0.8651 . it says , it's wrong

  32. yashar806
    • one year ago
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    now ,its right , thank you very much

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