anonymous
  • anonymous
Explain why each function is discontinuous at the given point. f(x) = x/x - 1 at x = 1
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
so what is discontinuous?
anonymous
  • anonymous
you mean the word discontinuous or?
anonymous
  • anonymous
yeah

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
well it means having a gap... missing doesn't continue
anonymous
  • anonymous
i don't get it. why would this function be discontinuous
anonymous
  • anonymous
because its saying that at point 1 it breaks its doesnt continue the line, so you have to explain why? why it broke?
anonymous
  • anonymous
@zepdrix can u help?
zepdrix
  • zepdrix
\[\large f(x)=\frac{x}{x-1}\] In the land of math, we are never allowed to divide by 0. If we let \(x=1\), it turns the denominator into \(0\). Which gives us a fraction of the form \(\dfrac{1}{0}\), which is no beuno!! See how we're dividing by 0? So we say that the function is undefined, or in other words, has a `discontinuity` at x=1.
zepdrix
  • zepdrix
If we were to look at it graphically, it forms an asymptote at x=1. Remember what type of discontinuity that is?
anonymous
  • anonymous
infinite right? lol
zepdrix
  • zepdrix
yes good c:
anonymous
  • anonymous
ok thanks
anonymous
  • anonymous
Good Good.

Looking for something else?

Not the answer you are looking for? Search for more explanations.