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Bladerunner1122
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Given an object in a straight line with a(t)=√t ft/sec^2 and v(0)=18 for t=0 to t=16, find v(t) and the displacement and distance of the object.
 one year ago
 one year ago
Bladerunner1122 Group Title
Given an object in a straight line with a(t)=√t ft/sec^2 and v(0)=18 for t=0 to t=16, find v(t) and the displacement and distance of the object.
 one year ago
 one year ago

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phi Group TitleBest ResponseYou've already chosen the best response.1
this sounds like an integration problem
 one year ago

Bladerunner1122 Group TitleBest ResponseYou've already chosen the best response.0
It is
 one year ago

Bladerunner1122 Group TitleBest ResponseYou've already chosen the best response.0
What's the thought process of the problem?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
velocity is \( \frac{dx}{dt} \) change in distance over change in time acceleration is \( \frac{dv}{dt} = \frac{d^2x}{dt^2} \) the second derivative of x with respect to time \[v= \int\limits_{0}^{16} \frac{dv}{dt} dt= \int\limits_{0}^{16} t^{\frac{1}{2}} dt\]
 one year ago
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