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 2 years ago
Given an object in a straight line with a(t)=√t ft/sec^2 and v(0)=18 for t=0 to t=16, find v(t) and the displacement and distance of the object.
 2 years ago
Given an object in a straight line with a(t)=√t ft/sec^2 and v(0)=18 for t=0 to t=16, find v(t) and the displacement and distance of the object.

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phi
 2 years ago
Best ResponseYou've already chosen the best response.1this sounds like an integration problem

Bladerunner1122
 2 years ago
Best ResponseYou've already chosen the best response.0What's the thought process of the problem?

phi
 2 years ago
Best ResponseYou've already chosen the best response.1velocity is \( \frac{dx}{dt} \) change in distance over change in time acceleration is \( \frac{dv}{dt} = \frac{d^2x}{dt^2} \) the second derivative of x with respect to time \[v= \int\limits_{0}^{16} \frac{dv}{dt} dt= \int\limits_{0}^{16} t^{\frac{1}{2}} dt\]
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