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 one year ago
Given an object in a straight line with a(t)=√t ft/sec^2 and v(0)=18 for t=0 to t=16, find v(t) and the displacement and distance of the object.
 one year ago
Given an object in a straight line with a(t)=√t ft/sec^2 and v(0)=18 for t=0 to t=16, find v(t) and the displacement and distance of the object.

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phi
 one year ago
Best ResponseYou've already chosen the best response.1this sounds like an integration problem

Bladerunner1122
 one year ago
Best ResponseYou've already chosen the best response.0What's the thought process of the problem?

phi
 one year ago
Best ResponseYou've already chosen the best response.1velocity is \( \frac{dx}{dt} \) change in distance over change in time acceleration is \( \frac{dv}{dt} = \frac{d^2x}{dt^2} \) the second derivative of x with respect to time \[v= \int\limits_{0}^{16} \frac{dv}{dt} dt= \int\limits_{0}^{16} t^{\frac{1}{2}} dt\]
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