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 one year ago
Find all discontinuities of f(x). For each discontinuity that is removable, define a new function that removes the discontinuity. f(x) = x  1/x^2  1
 one year ago
Find all discontinuities of f(x). For each discontinuity that is removable, define a new function that removes the discontinuity. f(x) = x  1/x^2  1

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tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0First, please remember your Order of Operations. You have NOT written \(\dfrac{x1}{x^{2}1}\). Give it another go and use more parentheses. Denominator = 0  Discontinuity. Is it an Asymptote or NonRemovable Discoutinuity? Numerator = 0 AT THE SAME PLACE, this it's Removable and NOT an Asymptote.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0?? There are two. 1) Which one are you talking about. 2) What's the other one?

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0removable discontinuity or infinite

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so it will be replacing 0 will give you discontity right? and not any other number?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Please make a better effort to use complete sentences and to be substantially more clear. I'll do a quick example. Sentences, paragraphs, examples, order. Working with the Denominator: \(x^{2}  1 = (x+1)(x1)\) This denominator takes on the value zero at x = 1 and x = 1. These values are NOT in the Domain and are discontinuities. We do not yet know what kind of discontinuity. Working with the Numerator x  1 = 0 when x = 1 This is enough information. x = 1 makes both Numerator and Denominator zero. This is, therefore, a removable discontinuity. Our original expression is equivalent to 1/(x+1) everywhere EXCEPT x = 1. x = 1 makes only the denominator zero. This is, therefore, an asymptote or infinite discontinuity. Now, we are done.
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