Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

onegirl

  • one year ago

Find all discontinuities of f(x). For each discontinuity that is removable, define a new function that removes the discontinuity. f(x) = x - 1/x^2 - 1

  • This Question is Closed
  1. tkhunny
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    First, please remember your Order of Operations. You have NOT written \(\dfrac{x-1}{x^{2}-1}\). Give it another go and use more parentheses. Denominator = 0 -- Discontinuity. Is it an Asymptote or NonRemovable Discoutinuity? Numerator = 0 AT THE SAME PLACE, this it's Removable and NOT an Asymptote.

  2. onegirl
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    non removable

  3. tkhunny
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?? There are two. 1) Which one are you talking about. 2) What's the other one?

  4. onegirl
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    removable discontinuity or infinite

  5. onegirl
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it will be replacing 0 will give you discontity right? and not any other number?

  6. tkhunny
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Please make a better effort to use complete sentences and to be substantially more clear. I'll do a quick example. Sentences, paragraphs, examples, order. Working with the Denominator: \(x^{2} - 1 = (x+1)(x-1)\) This denominator takes on the value zero at x = 1 and x = -1. These values are NOT in the Domain and are discontinuities. We do not yet know what kind of discontinuity. Working with the Numerator x - 1 = 0 when x = 1 This is enough information. x = 1 makes both Numerator and Denominator zero. This is, therefore, a removable discontinuity. Our original expression is equivalent to 1/(x+1) everywhere EXCEPT x = 1. x = -1 makes only the denominator zero. This is, therefore, an asymptote or infinite discontinuity. Now, we are done.

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.