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onegirl 3 years ago Use the Intermediate Value Theorem to verify that f(x) has a zero in the given interval. Then use the method of bisections to find an interval of length 1/32 that contains the zero.

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1. onegirl

f(x) = x^2 - 7, [2,3]

2. onegirl

can u help with this last one then i'm done for today @zepdrix

3. zepdrix

Well we can determine where f(x) has a zero by setting the function equal to zero and solving for x.$\large f(x)=x^2-7 \qquad \rightarrow \qquad 0=x^2-7 \qquad \rightarrow \qquad x=\sqrt 7$ $$\sqrt 7$$ is approximately $$2.65$$ which is between 2 and 3. I'm not exactly sure how to apply the Intermediate Value Theorem, or Bisections for that matter :( Hmmm But that's where the root is located at least :C

4. onegirl

okay thanks for the help i appreciate it

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