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P.nut1996

  • 3 years ago

I have no idea how to do this What is the equation of the line passing through (8, –6) and perpendicular to the line y = x – 2 in slope-intercept form?

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  1. ambius
    • 3 years ago
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    We know that the slope of our original equation is 1. What we need is the equation of a line that is perpendicular to y = x - 2. The "negative reciprocal" of the slope of our original equation of y=x-2 can be determined by taking the original slope of: \[\frac{ 1 }{ 1}\] and then flipping the numerator and the denominator. The amazing thing is this still gives us 1. However, it is the "negative" reciprocal. So, we multiply by -1. so, the beginning of our new equation is: \[y = -1 x + b\] Then, sub in (8, -6) into your new equation: \[-6=-1(8) + b\] we find that after solving for b: b=2 and our final equation is: y=-x+2

  2. P.nut1996
    • 3 years ago
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    That was very helpful! Thank you so much!

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