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P.nut1996
Group Title
I have no idea how to do this
What is the equation of the line passing through (8, –6) and perpendicular to the line y = x – 2 in slopeintercept form?
 one year ago
 one year ago
P.nut1996 Group Title
I have no idea how to do this What is the equation of the line passing through (8, –6) and perpendicular to the line y = x – 2 in slopeintercept form?
 one year ago
 one year ago

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ambius Group TitleBest ResponseYou've already chosen the best response.1
We know that the slope of our original equation is 1. What we need is the equation of a line that is perpendicular to y = x  2. The "negative reciprocal" of the slope of our original equation of y=x2 can be determined by taking the original slope of: \[\frac{ 1 }{ 1}\] and then flipping the numerator and the denominator. The amazing thing is this still gives us 1. However, it is the "negative" reciprocal. So, we multiply by 1. so, the beginning of our new equation is: \[y = 1 x + b\] Then, sub in (8, 6) into your new equation: \[6=1(8) + b\] we find that after solving for b: b=2 and our final equation is: y=x+2
 one year ago

P.nut1996 Group TitleBest ResponseYou've already chosen the best response.0
That was very helpful! Thank you so much!
 one year ago
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