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baldymcgee6

  • one year ago

A certain object of mass 3kg is dropped into a liquid and, as it falls through it, it is subject to the downward force of gravity and the upward force of drag, which is given by one fifth of its speed. Express this statement as a differential equation and solve such equation to identify the velocity function for the object.

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  1. baldymcgee6
    • one year ago
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    @zepdrix :)

  2. baldymcgee6
    • one year ago
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    I should be fine to solve the linear ODE, I just don't know where to start with contructing one.

  3. zepdrix
    • one year ago
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    hmm :(

  4. zepdrix
    • one year ago
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    hmm i dunno, this one is too "physics"y for me lol

  5. baldymcgee6
    • one year ago
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    haha, who else on here does calculus?

  6. zepdrix
    • one year ago
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    Hmm I dunno. There are a bunch of smarty pants online right now though :O Zarkon, Satellite, King George ...

  7. baldymcgee6
    • one year ago
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    @satellite73, @UnkleRhaukus ?

  8. baldymcgee6
    • one year ago
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    these guys probably get so many tags that they don't even bother.. lol... the joys of a 99 smartscore.

  9. baldymcgee6
    • one year ago
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    oh goody @hartnn came online :)

  10. hartnn
    • one year ago
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    seen such question for the first time, but still i'll give it a try... downward force of gravity =ma = mg (acceleration is due to gravity, so a=g) upward force of drag = ma = m dv/dt (v=velocity) given that mdv/dt = 1/5th of its speed = v/5 mdv/dt = v/5 in itself is a DE, donno how to incorporate mg ...

  11. hartnn
    • one year ago
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    v=velocity function ..

  12. baldymcgee6
    • one year ago
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    haha. Well that is a good start, I don't have any idea either of how to incorporate mg

  13. baldymcgee6
    • one year ago
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    Fnet = mg - v/5

  14. hartnn
    • one year ago
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    if the question meant that 'both' downward and upward forces together are 1/5th of speed, then m dv/dt -mg = v/5 ...

  15. baldymcgee6
    • one year ago
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    m*dv/dt = mg-v/5 ???

  16. hartnn
    • one year ago
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    or that^ i am still unsure..

  17. baldymcgee6
    • one year ago
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    no I think just the drag is v/5

  18. baldymcgee6
    • one year ago
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    hmm, I guess I will just go with one and see what I get.. :) thanks guys!

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