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 one year ago
A certain object of mass 3kg is dropped into a liquid and, as it falls through it, it is subject to the downward force of gravity and the upward force of drag, which is given by one fifth of its speed. Express this statement as a differential equation and solve such equation to identify the velocity function for the object.
 one year ago
A certain object of mass 3kg is dropped into a liquid and, as it falls through it, it is subject to the downward force of gravity and the upward force of drag, which is given by one fifth of its speed. Express this statement as a differential equation and solve such equation to identify the velocity function for the object.

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baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0I should be fine to solve the linear ODE, I just don't know where to start with contructing one.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0hmm i dunno, this one is too "physics"y for me lol

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0haha, who else on here does calculus?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Hmm I dunno. There are a bunch of smarty pants online right now though :O Zarkon, Satellite, King George ...

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73, @UnkleRhaukus ?

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0these guys probably get so many tags that they don't even bother.. lol... the joys of a 99 smartscore.

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0oh goody @hartnn came online :)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2seen such question for the first time, but still i'll give it a try... downward force of gravity =ma = mg (acceleration is due to gravity, so a=g) upward force of drag = ma = m dv/dt (v=velocity) given that mdv/dt = 1/5th of its speed = v/5 mdv/dt = v/5 in itself is a DE, donno how to incorporate mg ...

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0haha. Well that is a good start, I don't have any idea either of how to incorporate mg

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2if the question meant that 'both' downward and upward forces together are 1/5th of speed, then m dv/dt mg = v/5 ...

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0m*dv/dt = mgv/5 ???

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2or that^ i am still unsure..

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0no I think just the drag is v/5

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0hmm, I guess I will just go with one and see what I get.. :) thanks guys!
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