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StephyNea

  • 2 years ago

A job pays a salary of $25,000 the first year. During the next 22 years, the salary increases by 6% each year. What is the total lifetime salary over the 23-year period?

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  1. ambius
    • 2 years ago
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    \[tls = 25000(1.06)^{y-1}\]

  2. ambius
    • 2 years ago
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    so, when y=1, after the first year, he makes a salary of $25000. After that, his salary compounds at a rate of 6% per year, until y=23.

  3. ambius
    • 2 years ago
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    Also, remember that this equation calculates what his final salary is; not what he made over a 23 year period, lol

  4. ambius
    • 2 years ago
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    Maybe it would be better too look at it this way: "During" year 1: \[salary = 25000 *1.06^{1-1} = 25000*1 = $25000\] Salary during year 2: \[salary = 25000*1.06^{2-1} = 25000*1.06\] Salary during year 3: \[salary = 25000*1.06^{3-1} = 25000*1.06*1.06\] Salary during year 4: \[salary = 25000*1.06^{4-1} = 25000*1.06*1.06*1.06\] ...Until year 23, when you have multiplied the salary the individual received during his first year of 25000 buy 1.06 (or an increase of 6%) 22 times for each year his salary increases. The final amount is approximately: $90, 088.44

  5. StephyNea
    • 2 years ago
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    Thank you for your help. I was in the process of working it once my Aunt showed me how to do it, and I got the same thing. Thank you so much!

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