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kitsune0724

  • 2 years ago

x(x+12)=-28 I got (x+6)=-28. Is this correct? Please and Thank you.

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  1. Directrix
    • 2 years ago
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    @kitsune0724 Are you supposed to solve the given equation for x?

  2. matricked
    • 2 years ago
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    nope first multiply and then simplify and then

  3. kitsune0724
    • 2 years ago
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    @Directrix No you are suppose to find what would give the middle of the problem.

  4. Directrix
    • 2 years ago
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    @kitsune0724 I don't know what you mean by "middle of the problem." x(x+12)=-28 x^2 + 12x = -28 x^2 + 12x + 28 = 0 After that, I don't know what to say because I don't know the "middle."

  5. kitsune0724
    • 2 years ago
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    @Directrix would it be like this (x-12)^2=-28?

  6. Directrix
    • 2 years ago
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    @kitsune0724 I don't know because I don't understand what we are supposed to be doing. We need the directions / instructions for the problem.

  7. kitsune0724
    • 2 years ago
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    @Directrix Which of the following equations is equivalent to the equation in exercise 30? (In other words, which of these is an equation you should get in the MIDDLE of the completing the square process?) this is the problem.

  8. Azteck
    • 2 years ago
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    Oh...You complete the square...

  9. Azteck
    • 2 years ago
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    He forgot the ^2

  10. Directrix
    • 2 years ago
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    x(x+12)=-28 x^2 + 12x = -28 x^2 + 12x + 36 = -28 + 36 (x + 6)* (x+6) = 8 -----> Do you think we've made it to the middle yet. @kitsune0724

  11. kitsune0724
    • 2 years ago
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    @Directrix yes. that's what I got so far.

  12. Directrix
    • 2 years ago
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    (x + 6)* (x+6) = 8 (x + 6) = sqrt(8) OR (x + 6) = - sqrt (8) @kitsune0724

  13. kitsune0724
    • 2 years ago
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    @Directrix (x + 6) = - sqrt (8).

  14. Directrix
    • 2 years ago
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    @kitsune0724 What about this--> (x + 6) = sqrt(8) It is one of the two roots.

  15. kitsune0724
    • 2 years ago
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    @Directrix would it be x=6+2sqrt2, 6-2sqrt2?

  16. Directrix
    • 2 years ago
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    Not quite. I think you have a sign error. (x + 6) = sqrt(8) OR (x + 6) = - sqrt (8) @kitsune0724 x = -6 + sqrt(8) OR x = -6 - sqrt (8) x = -6 + 2sqrt2 or x = -6 -2sqrt2

  17. kitsune0724
    • 2 years ago
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    @Directrix x=-6+2sqrt2, -6-2sqrt2? I'm getting a bit confused here. Can you please draw it out for so I can what I'm doing wrong? Thank you.

  18. Directrix
    • 2 years ago
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    We're just subtracting 6 from both sides to solve for x. For example, (x + 6) = - sqrt (8). Subtract 6 from both sides. x+6 - 6 = -sqrt(8) - 6 x + 0 = -6 - sqrt(8) x = -6 - 2sqrt2 Same thinking for the second root. @kitsune0724

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