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kitsune0724

  • one year ago

x(x+12)=-28 I got (x+6)=-28. Is this correct? Please and Thank you.

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  1. Directrix
    • one year ago
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    @kitsune0724 Are you supposed to solve the given equation for x?

  2. matricked
    • one year ago
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    nope first multiply and then simplify and then

  3. kitsune0724
    • one year ago
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    @Directrix No you are suppose to find what would give the middle of the problem.

  4. Directrix
    • one year ago
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    @kitsune0724 I don't know what you mean by "middle of the problem." x(x+12)=-28 x^2 + 12x = -28 x^2 + 12x + 28 = 0 After that, I don't know what to say because I don't know the "middle."

  5. kitsune0724
    • one year ago
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    @Directrix would it be like this (x-12)^2=-28?

  6. Directrix
    • one year ago
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    @kitsune0724 I don't know because I don't understand what we are supposed to be doing. We need the directions / instructions for the problem.

  7. kitsune0724
    • one year ago
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    @Directrix Which of the following equations is equivalent to the equation in exercise 30? (In other words, which of these is an equation you should get in the MIDDLE of the completing the square process?) this is the problem.

  8. Azteck
    • one year ago
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    Oh...You complete the square...

  9. Azteck
    • one year ago
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    He forgot the ^2

  10. Directrix
    • one year ago
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    x(x+12)=-28 x^2 + 12x = -28 x^2 + 12x + 36 = -28 + 36 (x + 6)* (x+6) = 8 -----> Do you think we've made it to the middle yet. @kitsune0724

  11. kitsune0724
    • one year ago
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    @Directrix yes. that's what I got so far.

  12. Directrix
    • one year ago
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    (x + 6)* (x+6) = 8 (x + 6) = sqrt(8) OR (x + 6) = - sqrt (8) @kitsune0724

  13. kitsune0724
    • one year ago
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    @Directrix (x + 6) = - sqrt (8).

  14. Directrix
    • one year ago
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    @kitsune0724 What about this--> (x + 6) = sqrt(8) It is one of the two roots.

  15. kitsune0724
    • one year ago
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    @Directrix would it be x=6+2sqrt2, 6-2sqrt2?

  16. Directrix
    • one year ago
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    Not quite. I think you have a sign error. (x + 6) = sqrt(8) OR (x + 6) = - sqrt (8) @kitsune0724 x = -6 + sqrt(8) OR x = -6 - sqrt (8) x = -6 + 2sqrt2 or x = -6 -2sqrt2

  17. kitsune0724
    • one year ago
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    @Directrix x=-6+2sqrt2, -6-2sqrt2? I'm getting a bit confused here. Can you please draw it out for so I can what I'm doing wrong? Thank you.

  18. Directrix
    • one year ago
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    We're just subtracting 6 from both sides to solve for x. For example, (x + 6) = - sqrt (8). Subtract 6 from both sides. x+6 - 6 = -sqrt(8) - 6 x + 0 = -6 - sqrt(8) x = -6 - 2sqrt2 Same thinking for the second root. @kitsune0724

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