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melbelBest ResponseYou've already chosen the best response.0
\[\frac{ x4 }{ 2x+3 }\le3\]
 one year ago

melbelBest ResponseYou've already chosen the best response.0
My prof said that I can't multiply the 3 by the stuff in the denominator because the denominator contains an x. Since you don't know if x is going to be pos or negative, you can't determine whether or not you'll need to switch the sign. I have the answer, I just don't know how to solve it: \[(\infty, \frac{ 13 }{ 5 }]\cup(\frac{ 3 }{ 2 },\infty)\]
 one year ago
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