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katlin95
f(x)=sqrt 2x-5 find f (27)
substitute x with 27 in f(x) .
f(27)=sqr root (2(27)-5) Multiply 2 by the 27 inside the parentheses. f(27)=sqr root (2*27-5) Multiply 2 by 27 to get 54. f(27)=sqr root (54-5) Subtract 5 from 54 to get 49. f(27)=sqr root (49) Pull all perfect square roots out from under the radical. In this case, remove the 7 because it is a perfect square. f(27)=7
@AravindG is 7 correct?
@some_someone please do not give direct worked out answers like that .It is against Openstudy COC .Refer http://openstudy.com/code-of-conduct .Instead help the asker get to the solution ,making them participate in answering process.Thank you
Ok thank you @AravindG I will follow that now :)