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 one year ago
What is the range of the inverse of relation {(1, 7), (2, 4), (5, 6), (2, 8)}?
A.
{1, 2, 5}
B.
{4, 6, 7, 8}
C.
{1, 5}
D.
{4, 7, 8}
 one year ago
What is the range of the inverse of relation {(1, 7), (2, 4), (5, 6), (2, 8)}? A. {1, 2, 5} B. {4, 6, 7, 8} C. {1, 5} D. {4, 7, 8}

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some_someone
 one year ago
Best ResponseYou've already chosen the best response.0\[\left( 7,1 \right), \left( 4,2 \right)\left( 6,5 \right)\left( 8,2 \right)\]

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0this is the inverse ^^^^^^^^^^^^

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0\[RANGE=\left\{ 1,2,5 \right\}\]

Hoa
 one year ago
Best ResponseYou've already chosen the best response.1C) (1,5) the reason is your relation is pairs of number. consider the first number as x, and the second is y . your original function has x range from: 1,2,2,5 means the range is 1,5. from now on. you can say that the inverse is x is replace by y. so, in inverse function, you have y range from 1,5. and because it is inverse, the range does not depend on x value any more, but on y. so the answer is 1,5. I just want you to understand why the result is that and you can calculate by yourself in the future. Hope this help. @ some...someone. I'm sorry if I bother you. I just want to help the friend a little bit when i can.

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0No, the range of the inverse are the yvalues. which is (1,2,5)

Hoa
 one year ago
Best ResponseYou've already chosen the best response.1@some...someone. you are right. 100% right. I don't put 2 in the middle, because it is there already when the range go from1 to 5 , it includes 2
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