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mariana510

  • 3 years ago

can someone hep me with this problem please. Let A, B, C denote three rectangles, all with perimeter equal to 240, whose heights are h_A = 20, h_B = 60, h_C = 110, respectively. Which of the rectangles A, B, or C has the smallest area?

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  1. syhna
    • 3 years ago
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    i think its c

  2. mariana510
    • 3 years ago
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    thank you so much. I thought it was a but i got it wrong.

  3. syhna
    • 3 years ago
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    oh wait i think i got it wrong

  4. syhna
    • 3 years ago
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    P = 2b + 2h right?

  5. mariana510
    • 3 years ago
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    yes

  6. syhna
    • 3 years ago
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    240 = 2b + 2(20) 240 = 2b + 40 200 = 2b 100 = base of A do the same with the other rectangles 60 = base of B 10 = base of c A = b x h substitute the values then find which had the smallest area

  7. mariana510
    • 3 years ago
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    Thanks, also got base C with area 360

  8. syhna
    • 3 years ago
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    welcome

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