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can someone hep me with this problem please. Let A, B, C denote three rectangles, all with perimeter equal to 240, whose heights are h_A = 20, h_B = 60, h_C = 110, respectively. Which of the rectangles A, B, or C has the smallest area?

Geometry
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i think its c
thank you so much. I thought it was a but i got it wrong.
oh wait i think i got it wrong

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Other answers:

P = 2b + 2h right?
yes
240 = 2b + 2(20) 240 = 2b + 40 200 = 2b 100 = base of A do the same with the other rectangles 60 = base of B 10 = base of c A = b x h substitute the values then find which had the smallest area
Thanks, also got base C with area 360
welcome

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