anonymous
  • anonymous
can someone hep me with this problem please. Let A, B, C denote three rectangles, all with perimeter equal to 240, whose heights are h_A = 20, h_B = 60, h_C = 110, respectively. Which of the rectangles A, B, or C has the smallest area?
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
i think its c
anonymous
  • anonymous
thank you so much. I thought it was a but i got it wrong.
anonymous
  • anonymous
oh wait i think i got it wrong

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anonymous
  • anonymous
P = 2b + 2h right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
240 = 2b + 2(20) 240 = 2b + 40 200 = 2b 100 = base of A do the same with the other rectangles 60 = base of B 10 = base of c A = b x h substitute the values then find which had the smallest area
anonymous
  • anonymous
Thanks, also got base C with area 360
anonymous
  • anonymous
welcome

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