anonymous
  • anonymous
How do you find the domain and range of y=(1/x)-5?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
I already graphed.
anonymous
  • anonymous
|dw:1359707995799:dw|
anonymous
  • anonymous
notice the vertical asymptote... at x = ??? this should give you a hint for the domain... notice the horizontal asymptote... at y = ??? this should give you a hint for the range.

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skullpatrol
  • skullpatrol
What happens at x = 0?
jim_thompson5910
  • jim_thompson5910
Hint: To find the domain, find all the values of x that make the denominator equal to zero To find the range, find the inverse function and repeat the same steps to find the domain
anonymous
  • anonymous
I'm confused with this one because there are two lines. It throws me off. Should I put them together or what?
skullpatrol
  • skullpatrol
What do the "lines" mean?
anonymous
  • anonymous
I'm not really sure what they mean, they're just lines
anonymous
  • anonymous
The two curve lines
skullpatrol
  • skullpatrol
|dw:1359708410347:dw|
skullpatrol
  • skullpatrol
What is the domain and range of this equation?
anonymous
  • anonymous
This is what I'm having trouble with. I don't know how to find the domain and the range for these kinds of functions
skullpatrol
  • skullpatrol
The domain is all the values that you are allowed to input into the equation.
jim_thompson5910
  • jim_thompson5910
ignore the graph look at the equation y = (1/x) - 5 x cannot be 0 because if it were, then you would be dividing by zero (which is not allowed) so you must restrict 0 from the domain any other number is just fine So the domain is the set of all real numbers but x cannot be zero
jim_thompson5910
  • jim_thompson5910
the range can be found in a similar way, but you first need to find the inverse function
skullpatrol
  • skullpatrol
What would those be for $$y=\frac{1}{x}$$
anonymous
  • anonymous
What do you do after you find the inverse function?
jim_thompson5910
  • jim_thompson5910
what did you get for the inverse function
anonymous
  • anonymous
Actually, nevermind.
anonymous
  • anonymous
I want to be able to look at the graph and know the domain and the range
jim_thompson5910
  • jim_thompson5910
I'll show you how to get the inverse function Swap x and y, then solve for y y = (1/x) - 5 x = (1/y) - 5 x+5 = 1/y y(x+5) = 1 y = 1/(x+5) So the inverse function is y = 1/(x+5)
jim_thompson5910
  • jim_thompson5910
what makes the denominator x+5 equal to zero ?
jim_thompson5910
  • jim_thompson5910
we can go back to the graph after we do these equations
anonymous
  • anonymous
Wait, hold on. @skullpatrol is it |dw:1359709153164:dw|
skullpatrol
  • skullpatrol
Yes, and why?
skullpatrol
  • skullpatrol
|dw:1359709317420:dw|
skullpatrol
  • skullpatrol
|dw:1359709670237:dw|
skullpatrol
  • skullpatrol
Compare your graph to mine :)
anonymous
  • anonymous
That's what I got
anonymous
  • anonymous
x=/=0 y=/=-5

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