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anonymous
 3 years ago
How do you find the domain and range of y=(1/x)5?
anonymous
 3 years ago
How do you find the domain and range of y=(1/x)5?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359707995799:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0notice the vertical asymptote... at x = ??? this should give you a hint for the domain... notice the horizontal asymptote... at y = ??? this should give you a hint for the range.

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1What happens at x = 0?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1Hint: To find the domain, find all the values of x that make the denominator equal to zero To find the range, find the inverse function and repeat the same steps to find the domain

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm confused with this one because there are two lines. It throws me off. Should I put them together or what?

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1What do the "lines" mean?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not really sure what they mean, they're just lines

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359708410347:dw

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1What is the domain and range of this equation?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This is what I'm having trouble with. I don't know how to find the domain and the range for these kinds of functions

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1The domain is all the values that you are allowed to input into the equation.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1ignore the graph look at the equation y = (1/x)  5 x cannot be 0 because if it were, then you would be dividing by zero (which is not allowed) so you must restrict 0 from the domain any other number is just fine So the domain is the set of all real numbers but x cannot be zero

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1the range can be found in a similar way, but you first need to find the inverse function

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1What would those be for $$y=\frac{1}{x}$$

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you do after you find the inverse function?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1what did you get for the inverse function

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I want to be able to look at the graph and know the domain and the range

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1I'll show you how to get the inverse function Swap x and y, then solve for y y = (1/x)  5 x = (1/y)  5 x+5 = 1/y y(x+5) = 1 y = 1/(x+5) So the inverse function is y = 1/(x+5)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1what makes the denominator x+5 equal to zero ?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1we can go back to the graph after we do these equations

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait, hold on. @skullpatrol is it dw:1359709153164:dw

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359709317420:dw

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359709670237:dw

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.1Compare your graph to mine :)
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