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How do you find the domain and range of y=(1/x)-5?

Mathematics
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I already graphed.
|dw:1359707995799:dw|
notice the vertical asymptote... at x = ??? this should give you a hint for the domain... notice the horizontal asymptote... at y = ??? this should give you a hint for the range.

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Other answers:

What happens at x = 0?
Hint: To find the domain, find all the values of x that make the denominator equal to zero To find the range, find the inverse function and repeat the same steps to find the domain
I'm confused with this one because there are two lines. It throws me off. Should I put them together or what?
What do the "lines" mean?
I'm not really sure what they mean, they're just lines
The two curve lines
|dw:1359708410347:dw|
What is the domain and range of this equation?
This is what I'm having trouble with. I don't know how to find the domain and the range for these kinds of functions
The domain is all the values that you are allowed to input into the equation.
ignore the graph look at the equation y = (1/x) - 5 x cannot be 0 because if it were, then you would be dividing by zero (which is not allowed) so you must restrict 0 from the domain any other number is just fine So the domain is the set of all real numbers but x cannot be zero
the range can be found in a similar way, but you first need to find the inverse function
What would those be for $$y=\frac{1}{x}$$
What do you do after you find the inverse function?
what did you get for the inverse function
Actually, nevermind.
I want to be able to look at the graph and know the domain and the range
I'll show you how to get the inverse function Swap x and y, then solve for y y = (1/x) - 5 x = (1/y) - 5 x+5 = 1/y y(x+5) = 1 y = 1/(x+5) So the inverse function is y = 1/(x+5)
what makes the denominator x+5 equal to zero ?
we can go back to the graph after we do these equations
Wait, hold on. @skullpatrol is it |dw:1359709153164:dw|
Yes, and why?
|dw:1359709317420:dw|
|dw:1359709670237:dw|
Compare your graph to mine :)
That's what I got
x=/=0 y=/=-5

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