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sakigirl

  • one year ago

How do you find the domain and range of y=(1/x)-5?

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  1. sakigirl
    • one year ago
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    I already graphed.

  2. sakigirl
    • one year ago
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    |dw:1359707995799:dw|

  3. dpaInc
    • one year ago
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    notice the vertical asymptote... at x = ??? this should give you a hint for the domain... notice the horizontal asymptote... at y = ??? this should give you a hint for the range.

  4. skullpatrol
    • one year ago
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    What happens at x = 0?

  5. jim_thompson5910
    • one year ago
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    Hint: To find the domain, find all the values of x that make the denominator equal to zero To find the range, find the inverse function and repeat the same steps to find the domain

  6. sakigirl
    • one year ago
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    I'm confused with this one because there are two lines. It throws me off. Should I put them together or what?

  7. skullpatrol
    • one year ago
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    What do the "lines" mean?

  8. sakigirl
    • one year ago
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    I'm not really sure what they mean, they're just lines

  9. sakigirl
    • one year ago
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    The two curve lines

  10. skullpatrol
    • one year ago
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    |dw:1359708410347:dw|

  11. skullpatrol
    • one year ago
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    What is the domain and range of this equation?

  12. sakigirl
    • one year ago
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    This is what I'm having trouble with. I don't know how to find the domain and the range for these kinds of functions

  13. skullpatrol
    • one year ago
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    The domain is all the values that you are allowed to input into the equation.

  14. jim_thompson5910
    • one year ago
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    ignore the graph look at the equation y = (1/x) - 5 x cannot be 0 because if it were, then you would be dividing by zero (which is not allowed) so you must restrict 0 from the domain any other number is just fine So the domain is the set of all real numbers but x cannot be zero

  15. jim_thompson5910
    • one year ago
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    the range can be found in a similar way, but you first need to find the inverse function

  16. skullpatrol
    • one year ago
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    What would those be for $$y=\frac{1}{x}$$

  17. sakigirl
    • one year ago
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    What do you do after you find the inverse function?

  18. jim_thompson5910
    • one year ago
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    what did you get for the inverse function

  19. sakigirl
    • one year ago
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    Actually, nevermind.

  20. sakigirl
    • one year ago
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    I want to be able to look at the graph and know the domain and the range

  21. jim_thompson5910
    • one year ago
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    I'll show you how to get the inverse function Swap x and y, then solve for y y = (1/x) - 5 x = (1/y) - 5 x+5 = 1/y y(x+5) = 1 y = 1/(x+5) So the inverse function is y = 1/(x+5)

  22. jim_thompson5910
    • one year ago
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    what makes the denominator x+5 equal to zero ?

  23. jim_thompson5910
    • one year ago
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    we can go back to the graph after we do these equations

  24. sakigirl
    • one year ago
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    Wait, hold on. @skullpatrol is it |dw:1359709153164:dw|

  25. skullpatrol
    • one year ago
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    Yes, and why?

  26. skullpatrol
    • one year ago
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    |dw:1359709317420:dw|

  27. skullpatrol
    • one year ago
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    |dw:1359709670237:dw|

  28. skullpatrol
    • one year ago
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    Compare your graph to mine :)

  29. sakigirl
    • one year ago
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    That's what I got

  30. sakigirl
    • one year ago
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    x=/=0 y=/=-5

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