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cali2

  • 3 years ago

factorise y^3-10y+3

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  1. Yacoub1993
    • 3 years ago
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    \[y ^{3}-10y+3=0\] \[y ^{3}-10y=-3\] \[-9y ^{3}=-3\] \[y ^{3}=\frac{ -3 }{ -9 }\] \[y ^{3}=\frac{ 1 }{ 3 }\]

  2. klimenkov
    • 3 years ago
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    @Yacoub1993 Check the third step.

  3. Jonask
    • 3 years ago
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    y^3 and 10y not like terms???

  4. Yacoub1993
    • 3 years ago
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    ohh ok

  5. Jonask
    • 3 years ago
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    x-3 is a factor

  6. Yacoub1993
    • 3 years ago
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    mistaken didnt focus sorry

  7. Jonask
    • 3 years ago
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    \[(x-3)(x^2+3x-1)\]

  8. Yacoub1993
    • 3 years ago
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    go ahead next

  9. rizwan_uet
    • 3 years ago
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    y you are putting it equal to zero??? @Yacoub1993

  10. Jonask
    • 3 years ago
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    its finished like that

  11. Yacoub1993
    • 3 years ago
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    so that i factorize it

  12. rizwan_uet
    • 3 years ago
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    no no basically what you are trying to find a value of y such that if you put it in this equation will result in zero not to factorize it

  13. Yacoub1993
    • 3 years ago
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    ahha understood @rizwan_uet u should be my tutor for real :)

  14. rizwan_uet
    • 3 years ago
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    thanks Yacoub i will help you if you need

  15. rizwan_uet
    • 3 years ago
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    you have this y^3-10y+3 now we can write y^3+3y^2-3y^2-y-9y+3 y^3-3y^2+3y^2-9y-y+3 y^2(y-3)+3y(y-3)-1(y-3) can you do the last step??

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