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artix_17

  • 3 years ago

Partial derivative, pls help !! f(w,z)= w(w^2+z^2)^-1 Find f'w

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  1. klimenkov
    • 3 years ago
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    What is the biggest problem for you?

  2. artix_17
    • 3 years ago
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    I can't seem to get the answer

  3. klimenkov
    • 3 years ago
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    Do you know how to calculate the ordinary derivative, not the partial?

  4. artix_17
    • 3 years ago
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    Yes, for this question I use product rule, but just can't get the answer

  5. klimenkov
    • 3 years ago
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    Write here what you've got.

  6. klimenkov
    • 3 years ago
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    You can draw it using the "Draw" button.

  7. artix_17
    • 3 years ago
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    f'w = w X (-1)(w^2+z^2)^-2 X 2w + (w^2+z^2)^-1 (1) = -2w^3 (w^2+z^2) + (w^2+z^2)^-1

  8. artix_17
    • 3 years ago
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    = -2w^3 (w^2+z^2)^-2 + (w^2+z^2)^-1

  9. klimenkov
    • 3 years ago
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    You have to check the last answer very carefully. You are doing this right, but you are making mistakes. Check them.

  10. artix_17
    • 3 years ago
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    Which part is the mistake?

  11. klimenkov
    • 3 years ago
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    f'w = w X (-1)(w^2+z^2)^-2 X 2w + (w^2+z^2)^-1 - This is OK, but this = -2w^3 (w^2+z^2) + (w^2+z^2)^-1 is not. Try to find the common denominator in the first one and subtract the fractions.

  12. artix_17
    • 3 years ago
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    oh okay got it, thanks

  13. klimenkov
    • 3 years ago
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    You answered your question by yourself, I did not help you.

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