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artix_17
 3 years ago
Partial derivative, pls help !!
f(w,z)= w(w^2+z^2)^1
Find f'w
artix_17
 3 years ago
Partial derivative, pls help !! f(w,z)= w(w^2+z^2)^1 Find f'w

This Question is Closed

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1What is the biggest problem for you?

artix_17
 3 years ago
Best ResponseYou've already chosen the best response.0I can't seem to get the answer

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1Do you know how to calculate the ordinary derivative, not the partial?

artix_17
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, for this question I use product rule, but just can't get the answer

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1Write here what you've got.

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1You can draw it using the "Draw" button.

artix_17
 3 years ago
Best ResponseYou've already chosen the best response.0f'w = w X (1)(w^2+z^2)^2 X 2w + (w^2+z^2)^1 (1) = 2w^3 (w^2+z^2) + (w^2+z^2)^1

artix_17
 3 years ago
Best ResponseYou've already chosen the best response.0= 2w^3 (w^2+z^2)^2 + (w^2+z^2)^1

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1You have to check the last answer very carefully. You are doing this right, but you are making mistakes. Check them.

artix_17
 3 years ago
Best ResponseYou've already chosen the best response.0Which part is the mistake?

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1f'w = w X (1)(w^2+z^2)^2 X 2w + (w^2+z^2)^1  This is OK, but this = 2w^3 (w^2+z^2) + (w^2+z^2)^1 is not. Try to find the common denominator in the first one and subtract the fractions.

artix_17
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay got it, thanks

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1You answered your question by yourself, I did not help you.
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