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Mashy Group TitleBest ResponseYou've already chosen the best response.1
ah... so the first thing you need to do is calculate the location of the centre of mass.. can you do that?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Yeah, it's 1.95 m away from 1kg mass.
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Not sure what to do in next step...
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
ok.. i won't check that then.. fine.. now answer this.. if i know that there is a mass that is connected to a string.. which has a length 'l'.. and i swirled it.. what would be the moment of inertia???
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
dw:1359715230549:dw
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
\(\large I = \dfrac{1}{3}ml^2\), right?
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
noooOOO :O.. how did you get that? :O
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
its a point mass.. imagine its a point mass!!
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Idk, it's a formula for end of rod, though this is what you asked for, sorry
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
no.. what is the general formula for moment of inertia?? i think the concept itself is not clear to you.. huh?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
You mean \(\large I = ml^2\)?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
it's a general formula for inertia, i think.
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
its \[\sum_{ }^{ } mR ^{2}\]
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
thats the general formula.. and in my question .. since only one point mass is present.. you can say its just \[ml ^{2} \]
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
So for my question, I just use the sum of inertia?
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
so its basically summasation of all point mass times their distance from the axis of rotation squared.. so in your question.. you have 2 point masses.. so find each one's moment of inertia and sum it up
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
and don't call it inertia.. its called moment of inertia :P
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
inertia = resistance to change for linear motion moment of inertia = resistance to change for rotational motion
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
ok I see. does this formula \(\displaystyle\int r^2 \text{d}m\) work too? I tired this way and I got lost.
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
that is only if you have a rigid object.(continuos distribution of mass). but in your case its not a rigit object... its just 2 point masses.. !! so you can indivisually find their moment's of inertia about the rotational axis and sum them up..
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
I see. Thanks!
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
your welcome :)
 one year ago
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