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Mashy
 one year ago
Best ResponseYou've already chosen the best response.1ah... so the first thing you need to do is calculate the location of the centre of mass.. can you do that?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, it's 1.95 m away from 1kg mass.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Not sure what to do in next step...

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1ok.. i won't check that then.. fine.. now answer this.. if i know that there is a mass that is connected to a string.. which has a length 'l'.. and i swirled it.. what would be the moment of inertia???

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1\(\large I = \dfrac{1}{3}ml^2\), right?

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1noooOOO :O.. how did you get that? :O

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1its a point mass.. imagine its a point mass!!

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Idk, it's a formula for end of rod, though this is what you asked for, sorry

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1no.. what is the general formula for moment of inertia?? i think the concept itself is not clear to you.. huh?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1You mean \(\large I = ml^2\)?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1it's a general formula for inertia, i think.

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1its \[\sum_{ }^{ } mR ^{2}\]

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1thats the general formula.. and in my question .. since only one point mass is present.. you can say its just \[ml ^{2} \]

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1So for my question, I just use the sum of inertia?

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1so its basically summasation of all point mass times their distance from the axis of rotation squared.. so in your question.. you have 2 point masses.. so find each one's moment of inertia and sum it up

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1and don't call it inertia.. its called moment of inertia :P

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1inertia = resistance to change for linear motion moment of inertia = resistance to change for rotational motion

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1ok I see. does this formula \(\displaystyle\int r^2 \text{d}m\) work too? I tired this way and I got lost.

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1that is only if you have a rigid object.(continuos distribution of mass). but in your case its not a rigit object... its just 2 point masses.. !! so you can indivisually find their moment's of inertia about the rotational axis and sum them up..
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