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TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge(a ^{4})^{3} \]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0\[ \huge a= (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0i just sub a equal whatever in a^12 but i can never get it right

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1(a^4)^3 = a^(4*3) (a^4)^3 = a^(12) So if you want to find (a^4)^3, then you can find a^(12) instead since they are the same

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[ \Large a= (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\] \[ \Large a^{12}\] \[ \Large \left((\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\right)^{12}\] \[ \Large (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 } * 12}\] \[ \Large (\frac{ 2 }{ 3 })^{\frac{ 12 }{ 6 }}\] \[ \Large (\frac{ 2 }{ 3 })^{2}\] I'll let you finish

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0so the final answer is 4r9?

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0wow thanks so much anyways

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you mean 4/9 right?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1not sure how/where the r comes into play

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1btw \[\Large \frac{4}{9} = 4/9\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0oh lol in my calc to write something over something its something r something :P

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1oh interesting, never seen or heard of that before

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0actaully some question written in australia are written 8r9 which means 8/9

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1i gotcha, that makes more sense now

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1never ever seen that notation before
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