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TeemoTheTerificBest ResponseYou've already chosen the best response.0
\[\huge(a ^{4})^{3} \]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
\[ \huge a= (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
i just sub a equal whatever in a^12 but i can never get it right
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
(a^4)^3 = a^(4*3) (a^4)^3 = a^(12) So if you want to find (a^4)^3, then you can find a^(12) instead since they are the same
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
\[ \Large a= (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\] \[ \Large a^{12}\] \[ \Large \left((\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\right)^{12}\] \[ \Large (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 } * 12}\] \[ \Large (\frac{ 2 }{ 3 })^{\frac{ 12 }{ 6 }}\] \[ \Large (\frac{ 2 }{ 3 })^{2}\] I'll let you finish
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
so the final answer is 4r9?
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
wow thanks so much anyways
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
you mean 4/9 right?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
not sure how/where the r comes into play
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
btw \[\Large \frac{4}{9} = 4/9\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
oh lol in my calc to write something over something its something r something :P
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
oh interesting, never seen or heard of that before
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
actaully some question written in australia are written 8r9 which means 8/9
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
i gotcha, that makes more sense now
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
never ever seen that notation before
 one year ago
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