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\[\huge(a ^{4})^{3} \]

\[ \huge a= (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\]

evaluate

i just sub a equal whatever in a^12 but i can never get it right

so the final answer is 4r9?

wow thanks so much anyways

you mean 4/9 right?

not sure how/where the r comes into play

btw \[\Large \frac{4}{9} = 4/9\]

oh lol in my calc to write something over something its something r something :P

oh interesting, never seen or heard of that before

actaully some question written in australia are written 8r9 which means 8/9

i gotcha, that makes more sense now

never ever seen that notation before