A community for students.
Here's the question you clicked on:
 0 viewing
rinoa1989
 3 years ago
Hi I need help for a question here related to Circle as attached below. Please help Thanks! ><"
rinoa1989
 3 years ago
Hi I need help for a question here related to Circle as attached below. Please help Thanks! ><"

This Question is Closed

rinoa1989
 3 years ago
Best ResponseYou've already chosen the best response.0The answer given is A

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2do you know the central angle and corresponding arc property ...like dw:1359727764547:dw if central angle given is 70 degrees ,say, then can you find length of arc p and angle q ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2i meant length of arc q and angle p...

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1you can create isocolese triangles from central angles.dw:1359728013730:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2for your question, i extended WO to meet circle at say L dw:1359727980102:dw

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1i think working the iso triangle with the 65 would be simpler :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359728146814:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2oh, but i figured it out the using other method, i think..and i donno how that would help...maybe you can proceed to show us...

rinoa1989
 3 years ago
Best ResponseYou've already chosen the best response.0omg looks so complicated! LOL ><"

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1the base angles of an iso tri are equal; leaving the central angle to be 180  2base; in this case, 180  2(65) total arc length is then 70 + 180  2base and x is determined to be half that

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yeah...i figured arc WV = 50 using similar thing, which is essentially similar to what u did..

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2my way... arc WV+VU+UL = 180 but since angle LWV = 65 , VU+UL = 130 which gives WV = 50 then 2x = 70 +WV

rinoa1989
 3 years ago
Best ResponseYou've already chosen the best response.0wait let me digest first lol

rinoa1989
 3 years ago
Best ResponseYou've already chosen the best response.0i duno how u get this arc WV+VU+UL = 180

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2since is O the centre, arc WL is semicircle WL = 180 WV+VU+UL = 180

rinoa1989
 3 years ago
Best ResponseYou've already chosen the best response.0ic ok how bout this one 2x = 70 +WV ??

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1359729747346:dw so 2x = 70+WV

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2thats why i first asked you whether you know that property....

rinoa1989
 3 years ago
Best ResponseYou've already chosen the best response.0sorry i duno about that property i tot it is related to the photo i attach here

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2its the same property i illustrated.. angle A = x= 1/2 of central angle O(2x) = 1/2 of arc QP so, here x = half of arc TV x= TV/2 2x=TV = 70+WV....

rinoa1989
 3 years ago
Best ResponseYou've already chosen the best response.0oops ic ok! coz i just use the 70 to divide 2 to find x now i understand thank you so much for your time in explaining! ><"
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.