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 2 years ago
Hi I need help for a question here related to Circle as attached below. Please help Thanks! ><"
 2 years ago
Hi I need help for a question here related to Circle as attached below. Please help Thanks! ><"

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rinoa1989
 2 years ago
Best ResponseYou've already chosen the best response.0The answer given is A

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2do you know the central angle and corresponding arc property ...like dw:1359727764547:dw if central angle given is 70 degrees ,say, then can you find length of arc p and angle q ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i meant length of arc q and angle p...

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1you can create isocolese triangles from central angles.dw:1359728013730:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2for your question, i extended WO to meet circle at say L dw:1359727980102:dw

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1i think working the iso triangle with the 65 would be simpler :)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1359728146814:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2oh, but i figured it out the using other method, i think..and i donno how that would help...maybe you can proceed to show us...

rinoa1989
 2 years ago
Best ResponseYou've already chosen the best response.0omg looks so complicated! LOL ><"

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1the base angles of an iso tri are equal; leaving the central angle to be 180  2base; in this case, 180  2(65) total arc length is then 70 + 180  2base and x is determined to be half that

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2yeah...i figured arc WV = 50 using similar thing, which is essentially similar to what u did..

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2my way... arc WV+VU+UL = 180 but since angle LWV = 65 , VU+UL = 130 which gives WV = 50 then 2x = 70 +WV

rinoa1989
 2 years ago
Best ResponseYou've already chosen the best response.0wait let me digest first lol

rinoa1989
 2 years ago
Best ResponseYou've already chosen the best response.0i duno how u get this arc WV+VU+UL = 180

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2since is O the centre, arc WL is semicircle WL = 180 WV+VU+UL = 180

rinoa1989
 2 years ago
Best ResponseYou've already chosen the best response.0ic ok how bout this one 2x = 70 +WV ??

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1359729747346:dw so 2x = 70+WV

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2thats why i first asked you whether you know that property....

rinoa1989
 2 years ago
Best ResponseYou've already chosen the best response.0sorry i duno about that property i tot it is related to the photo i attach here

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2its the same property i illustrated.. angle A = x= 1/2 of central angle O(2x) = 1/2 of arc QP so, here x = half of arc TV x= TV/2 2x=TV = 70+WV....

rinoa1989
 2 years ago
Best ResponseYou've already chosen the best response.0oops ic ok! coz i just use the 70 to divide 2 to find x now i understand thank you so much for your time in explaining! ><"
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