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 one year ago
Find an equation of a plane containing the line r=(1,5,4) + t(9,6,3) which is parallel to the plane 3x + 2y  5y +28 in which the coefficient of x is 3.
 one year ago
Find an equation of a plane containing the line r=(1,5,4) + t(9,6,3) which is parallel to the plane 3x + 2y  5y +28 in which the coefficient of x is 3.

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1if you cross the direction vector of the line with the normal of the plane you will get a new vector that you can anchor to the lines point to define another point in the parallel plane

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359729417959:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1lol, thats a bad drawing

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1my idea might have a flaw in it .....

mags093
 one year ago
Best ResponseYou've already chosen the best response.0i got the normal vector which is (3,2,5)? and then Po=(1,5,4)? then used the dot product so that 3(1x)2(5y)5(4z)=o but it keeps saying its wrong? how do i get a new vector from the normal vector?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1direction vector of the line is: <9,6,3>, or reduced to <3,2,1> the normal vector is as you stated: <3,2,5> my idea is to cross these 2 vectors to find a new vector but I cant really see it being able to define a parallel plane perse. I can develop a perpendicular place tho

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the dot product of the normal and direction vectors is: 3, 2,1 3,2,5  9+4+5 = 0 so the vetcors themselves are already perped to each other

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1so basically its asking to use the normal given and the point given to define a parallel plane

mags093
 one year ago
Best ResponseYou've already chosen the best response.0ok so how would i get the equation of the plane?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.13(xpx) + 2(ypy)  5(zpz) + d = 0

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the +d was spurious on my part, im abit sick today :) given point is: (1,5,4) 3(x+1) + 2(y5)  5(z+4) = 0 3x3 +2y10  5z20 3x + 2y 5z 33 = 0 your setup was fine except it starts with a +3x not a 3x

mags093
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much :) it was right
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