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Could anyone help with this? i got as far as sqrt(4) * sin[coz^1(sqrt(4)/ 2sqrt(22)] but its wrong? Find the distance the point P(1,5,5) is to the line through the two points
Q(1,2,5), and R(4,4,2).
 one year ago
 one year ago
Could anyone help with this? i got as far as sqrt(4) * sin[coz^1(sqrt(4)/ 2sqrt(22)] but its wrong? Find the distance the point P(1,5,5) is to the line through the two points Q(1,2,5), and R(4,4,2).
 one year ago
 one year ago

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amistre64Best ResponseYou've already chosen the best response.0
dw:1359730906752:dw
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
\[cos\alpha=\frac{u.v}{u~v}\] \[\alpha=cos^{1}\frac{u.v}{u~v}\] \[PQ~sin~\alpha=PQ~cos^{1}\frac{u.v}{u~v}\]
 one year ago

mags093Best ResponseYou've already chosen the best response.0
i had this formula: [((sqrt(ad)^2 +(be)^2+(cf)^2 * sin(c0s^1([(ad)g + (be)h + (cf)i] / sqrt(ad)^2 +(be)^2+(cf)^2 sqrtg^2+h^2=i^2]))
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
i never remember formulas to well so I tend to have to reconstruct a method that will work out :) that was the simplest one I could manufacture :)
 one year ago

mags093Best ResponseYou've already chosen the best response.0
i dont understand your method as we did the other one! could you show me how to use yours?
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
I know the basic formula to fine the angle between QR and PQ, i know that the distance is a perp line value from P to R; which is equal to the hypotenuse times the sine of the angle. P(1,5,5) Q(1,2,5)  <0,3,0>; PQ = 3 Q(1,2,5) R(4,4,2).  <3,2,3>; QR = sqrt(22) im curious if they gave us a rt triangle to begin with now :)
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
P(1,5,5) R(4,4,2)  <3,1,3> <0,3,0>pq <3,2,3>qr <3,1,3>pr <3,1,3>pr  0+3+0 9+92 <0,3,0>pq <3,2,3>qr  06+0 nope, nothings at right angles to begin with :)
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
\[3~cos^{1}\frac{6}{3\sqrt{22}}=abt~6.034\] is the distance from the line to the given point.
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
dw:1359731838243:dw
 one year ago

mags093Best ResponseYou've already chosen the best response.0
so it should be 3sqrt22 not 2sqrt22?
 one year ago
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