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mags093
 3 years ago
Could anyone help with this? i got as far as sqrt(4) * sin[coz^1(sqrt(4)/ 2sqrt(22)] but its wrong? Find the distance the point P(1,5,5) is to the line through the two points
Q(1,2,5), and R(4,4,2).
mags093
 3 years ago
Could anyone help with this? i got as far as sqrt(4) * sin[coz^1(sqrt(4)/ 2sqrt(22)] but its wrong? Find the distance the point P(1,5,5) is to the line through the two points Q(1,2,5), and R(4,4,2).

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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359730906752:dw

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[cos\alpha=\frac{u.v}{u~v}\] \[\alpha=cos^{1}\frac{u.v}{u~v}\] \[PQ~sin~\alpha=PQ~cos^{1}\frac{u.v}{u~v}\]

mags093
 3 years ago
Best ResponseYou've already chosen the best response.0i had this formula: [((sqrt(ad)^2 +(be)^2+(cf)^2 * sin(c0s^1([(ad)g + (be)h + (cf)i] / sqrt(ad)^2 +(be)^2+(cf)^2 sqrtg^2+h^2=i^2]))

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0i never remember formulas to well so I tend to have to reconstruct a method that will work out :) that was the simplest one I could manufacture :)

mags093
 3 years ago
Best ResponseYou've already chosen the best response.0i dont understand your method as we did the other one! could you show me how to use yours?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0I know the basic formula to fine the angle between QR and PQ, i know that the distance is a perp line value from P to R; which is equal to the hypotenuse times the sine of the angle. P(1,5,5) Q(1,2,5)  <0,3,0>; PQ = 3 Q(1,2,5) R(4,4,2).  <3,2,3>; QR = sqrt(22) im curious if they gave us a rt triangle to begin with now :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0P(1,5,5) R(4,4,2)  <3,1,3> <0,3,0>pq <3,2,3>qr <3,1,3>pr <3,1,3>pr  0+3+0 9+92 <0,3,0>pq <3,2,3>qr  06+0 nope, nothings at right angles to begin with :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[3~cos^{1}\frac{6}{3\sqrt{22}}=abt~6.034\] is the distance from the line to the given point.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359731838243:dw

mags093
 3 years ago
Best ResponseYou've already chosen the best response.0so it should be 3sqrt22 not 2sqrt22?
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