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Micah and Delanie are in the a soapboc cart derby. Thay are about to crash into each other. They both are buckled into their respective carts and when they have their inelastic collision, they all go at a speed of 0.40 m/s in the direction frm which Micah was originally coming. If Micah's total cart mass (including himself) was 120. kg and Delanie's total cart mass (including herself) was 85.0kg, what would be the speed of each cart if the total energy "lost" in the collision was 1672.8J?

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@amistre64 please helpppp
hmm \[120v1+85v2=285(.4)+1672.8\] is what my idea is

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of course making sure the energy lost is put in proper relation
i know im pretty lost. i have to got to class. ill let you know aht the answers is and how my techer did it later. thanks for the help.
k, ill see what i can do on my own to see if my idea has any merit :)
and thats spose to be 205, not 285 ... typo :)
the energy in the system as it stands is: 205(.4)^2/2 = 16.4 J add that to what was lost; 1672.8 + 16.4 ------ 1689.2 kg m^2/s^2 = Mv^2/2 =102.5kg v3 m^2/s2 1689.2/102.5 = (v3)^2 sqrt(16.48) = v3 v3 is about 4.06 m/s if im thinking this correctly :)
this at least gives me an equation: 120 v1 + 85 v2 = 205(4.06) if i could see another way to determine a second equation in v1 and v2 we would have 2 eqs in 2 unknowns
im thinking that maybe: 120/2 v1^2 + 85/2 v2^2 = 1689.2 kg m^2/s^2 60 v1^2 + 42.5 v2^2 = 1689.2 but i think im just going in circles .... oh well
v2 = sqrt((1689.2 - 60x)/42.5) 120 v1 + 85 sqrt((1689.2 - 60x)/42.5) = 205(4.06) the calculations give me v1 as about 2.69 v2 as about 5.99 ifn i did it correctly to begin with :)
yeah you did you got it right!

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