A community for students.
Here's the question you clicked on:
 0 viewing
meg1334
 3 years ago
will give medal to best answer!
The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used.
C = 38°, a = 19, c = 10
meg1334
 3 years ago
will give medal to best answer! The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used. C = 38°, a = 19, c = 10

This Question is Closed

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Did you try simply using Law of Sines to figure it out?

meg1334
 3 years ago
Best ResponseYou've already chosen the best response.0yes but i didnt understand

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4What did you come up with?

meg1334
 3 years ago
Best ResponseYou've already chosen the best response.0i got sin A = 67 but that isnt in my answer choices No triangle is formed. A = 58.6°, B = 83.4°, b ≈ 15.6 A = 83.4°, B = 58.6°, b ≈ 15.6 The triangle cannot be solved with the Law of Sines.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4I don't understand how you got that. Please show me the steps you took to get A = 67

meg1334
 3 years ago
Best ResponseYou've already chosen the best response.0i used c/ sin c = a/ sin a 10/sin 37 = 19/sin a and then i divided 19 sin 38 over sin 10 and i got 67.36

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4where did you get the 37 from?

meg1334
 3 years ago
Best ResponseYou've already chosen the best response.0I meant 38, i used 38 in my claculations and still got 67

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Are you in degree mode or radian mode?

meg1334
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know i just typed it in and got 67, cant you check it?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4You must make sure you're in degree mode. That's very important.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4But either way it goes, you're not doing it correctly.

meg1334
 3 years ago
Best ResponseYou've already chosen the best response.0oh really, i hadnt noticed that im doing it wrong. I need help thats why im on here obviously

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4\[\sin A = \frac{19\sin(38^{\circ})}{10} \\\sin A = \]

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Compute the right hand side again and let me know what you get. Make sure you're in degree mode.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Okay now \[\sin A = 1.169756803\] So how do we find A?

meg1334
 3 years ago
Best ResponseYou've already chosen the best response.0a is 19, sin A is 1.16, what do you mean find A?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4I'm not talking about a = 19. That's a side length

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4\[\sin (A^{\circ}) = 1.169756803\] I'm talking about Angle A. Find that.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4You take the inverse sine of both sides to get: \[\sin^{1}(A^{\circ}) = \sin^{1}({1.169756803}) \\A^{\circ} = \sin^{1}({1.169756803}) \]

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4So compute \[\sin^{1}({1.169756803})\]

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4That's what it should say because no such angle exists.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4And if the angle doesn't exist, then the triangle can't possibly exist.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4\[1< \sin(\theta) < 1\] means that the value of sine can only be between  or + one. So there's no such thing as \(\sin(\theta) = 1.17\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.