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anonymous
 3 years ago
will give medal to best answer!
The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used.
C = 38°, a = 19, c = 10
anonymous
 3 years ago
will give medal to best answer! The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used. C = 38°, a = 19, c = 10

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Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Did you try simply using Law of Sines to figure it out?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes but i didnt understand

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4What did you come up with?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got sin A = 67 but that isnt in my answer choices No triangle is formed. A = 58.6°, B = 83.4°, b ≈ 15.6 A = 83.4°, B = 58.6°, b ≈ 15.6 The triangle cannot be solved with the Law of Sines.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4I don't understand how you got that. Please show me the steps you took to get A = 67

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i used c/ sin c = a/ sin a 10/sin 37 = 19/sin a and then i divided 19 sin 38 over sin 10 and i got 67.36

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4where did you get the 37 from?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I meant 38, i used 38 in my claculations and still got 67

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Are you in degree mode or radian mode?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know i just typed it in and got 67, cant you check it?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4You must make sure you're in degree mode. That's very important.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4But either way it goes, you're not doing it correctly.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh really, i hadnt noticed that im doing it wrong. I need help thats why im on here obviously

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4\[\sin A = \frac{19\sin(38^{\circ})}{10} \\\sin A = \]

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Compute the right hand side again and let me know what you get. Make sure you're in degree mode.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4Okay now \[\sin A = 1.169756803\] So how do we find A?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a is 19, sin A is 1.16, what do you mean find A?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4I'm not talking about a = 19. That's a side length

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4\[\sin (A^{\circ}) = 1.169756803\] I'm talking about Angle A. Find that.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4You take the inverse sine of both sides to get: \[\sin^{1}(A^{\circ}) = \sin^{1}({1.169756803}) \\A^{\circ} = \sin^{1}({1.169756803}) \]

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4So compute \[\sin^{1}({1.169756803})\]

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4That's what it should say because no such angle exists.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4And if the angle doesn't exist, then the triangle can't possibly exist.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.4\[1< \sin(\theta) < 1\] means that the value of sine can only be between  or + one. So there's no such thing as \(\sin(\theta) = 1.17\)
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