anonymous
  • anonymous
will give medal to best answer! The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used. C = 38°, a = 19, c = 10
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Hero
  • Hero
Did you try simply using Law of Sines to figure it out?
anonymous
  • anonymous
yes but i didnt understand
Hero
  • Hero
What did you come up with?

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More answers

anonymous
  • anonymous
i got sin A = 67 but that isnt in my answer choices No triangle is formed. A = 58.6°, B = 83.4°, b ≈ 15.6 A = 83.4°, B = 58.6°, b ≈ 15.6 The triangle cannot be solved with the Law of Sines.
Hero
  • Hero
I don't understand how you got that. Please show me the steps you took to get A = 67
anonymous
  • anonymous
i used c/ sin c = a/ sin a 10/sin 37 = 19/sin a and then i divided 19 sin 38 over sin 10 and i got 67.36
Hero
  • Hero
where did you get the 37 from?
anonymous
  • anonymous
I meant 38, i used 38 in my claculations and still got 67
anonymous
  • anonymous
calculations
Hero
  • Hero
Are you in degree mode or radian mode?
anonymous
  • anonymous
i dont know i just typed it in and got 67, cant you check it?
Hero
  • Hero
You must make sure you're in degree mode. That's very important.
Hero
  • Hero
But either way it goes, you're not doing it correctly.
anonymous
  • anonymous
oh really, i hadnt noticed that im doing it wrong. I need help thats why im on here obviously
Hero
  • Hero
\[\sin A = \frac{19\sin(38^{\circ})}{10} \\\sin A = \]
Hero
  • Hero
Compute the right hand side again and let me know what you get. Make sure you're in degree mode.
anonymous
  • anonymous
1.169756803
Hero
  • Hero
Okay now \[\sin A = 1.169756803\] So how do we find A?
anonymous
  • anonymous
a is 19, sin A is 1.16, what do you mean find A?
Hero
  • Hero
A is an angle. Find it
Hero
  • Hero
A is an Angle like theta
Hero
  • Hero
I'm not talking about a = 19. That's a side length
Hero
  • Hero
\[\sin (A^{\circ}) = 1.169756803\] I'm talking about Angle A. Find that.
anonymous
  • anonymous
how?
Hero
  • Hero
You take the inverse sine of both sides to get: \[\sin^{-1}(A^{\circ}) = \sin^{-1}({1.169756803}) \\A^{\circ} = \sin^{-1}({1.169756803}) \]
Hero
  • Hero
So compute \[\sin^{-1}({1.169756803})\]
Hero
  • Hero
Let me know what you get.
anonymous
  • anonymous
it says error
Hero
  • Hero
Exactly.
Hero
  • Hero
That's what it should say because no such angle exists.
Hero
  • Hero
And if the angle doesn't exist, then the triangle can't possibly exist.
Hero
  • Hero
\[-1< \sin(\theta) < 1\] means that the value of sine can only be between - or + one. So there's no such thing as \(\sin(\theta) = 1.17\)

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