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Did you try simply using Law of Sines to figure it out?

yes but i didnt understand

What did you come up with?

I don't understand how you got that. Please show me the steps you took to get A = 67

where did you get the 37 from?

I meant 38, i used 38 in my claculations and still got 67

calculations

Are you in degree mode or radian mode?

i dont know i just typed it in and got 67, cant you check it?

You must make sure you're in degree mode. That's very important.

But either way it goes, you're not doing it correctly.

oh really, i hadnt noticed that im doing it wrong. I need help thats why im on here obviously

\[\sin A = \frac{19\sin(38^{\circ})}{10}
\\\sin A =
\]

Compute the right hand side again and let me know what you get. Make sure you're in degree mode.

1.169756803

Okay now
\[\sin A = 1.169756803\]
So how do we find A?

a is 19, sin A is 1.16, what do you mean find A?

A is an angle. Find it

A is an Angle like theta

I'm not talking about a = 19. That's a side length

\[\sin (A^{\circ}) = 1.169756803\]
I'm talking about Angle A. Find that.

how?

So compute \[\sin^{-1}({1.169756803})\]

Let me know what you get.

it says error

Exactly.

That's what it should say because no such angle exists.

And if the angle doesn't exist, then the triangle can't possibly exist.