## meg1334 Group Title will give medal to best answer! The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used. C = 38°, a = 19, c = 10 one year ago one year ago

1. Hero Group Title

Did you try simply using Law of Sines to figure it out?

2. meg1334 Group Title

yes but i didnt understand

3. Hero Group Title

What did you come up with?

4. meg1334 Group Title

i got sin A = 67 but that isnt in my answer choices No triangle is formed. A = 58.6°, B = 83.4°, b ≈ 15.6 A = 83.4°, B = 58.6°, b ≈ 15.6 The triangle cannot be solved with the Law of Sines.

5. Hero Group Title

I don't understand how you got that. Please show me the steps you took to get A = 67

6. meg1334 Group Title

i used c/ sin c = a/ sin a 10/sin 37 = 19/sin a and then i divided 19 sin 38 over sin 10 and i got 67.36

7. Hero Group Title

where did you get the 37 from?

8. meg1334 Group Title

I meant 38, i used 38 in my claculations and still got 67

9. meg1334 Group Title

calculations

10. Hero Group Title

Are you in degree mode or radian mode?

11. meg1334 Group Title

i dont know i just typed it in and got 67, cant you check it?

12. Hero Group Title

You must make sure you're in degree mode. That's very important.

13. Hero Group Title

But either way it goes, you're not doing it correctly.

14. meg1334 Group Title

oh really, i hadnt noticed that im doing it wrong. I need help thats why im on here obviously

15. Hero Group Title

$\sin A = \frac{19\sin(38^{\circ})}{10} \\\sin A =$

16. Hero Group Title

Compute the right hand side again and let me know what you get. Make sure you're in degree mode.

17. meg1334 Group Title

1.169756803

18. Hero Group Title

Okay now $\sin A = 1.169756803$ So how do we find A?

19. meg1334 Group Title

a is 19, sin A is 1.16, what do you mean find A?

20. Hero Group Title

A is an angle. Find it

21. Hero Group Title

A is an Angle like theta

22. Hero Group Title

I'm not talking about a = 19. That's a side length

23. Hero Group Title

$\sin (A^{\circ}) = 1.169756803$ I'm talking about Angle A. Find that.

24. meg1334 Group Title

how?

25. Hero Group Title

You take the inverse sine of both sides to get: $\sin^{-1}(A^{\circ}) = \sin^{-1}({1.169756803}) \\A^{\circ} = \sin^{-1}({1.169756803})$

26. Hero Group Title

So compute $\sin^{-1}({1.169756803})$

27. Hero Group Title

Let me know what you get.

28. meg1334 Group Title

it says error

29. Hero Group Title

Exactly.

30. Hero Group Title

That's what it should say because no such angle exists.

31. Hero Group Title

And if the angle doesn't exist, then the triangle can't possibly exist.

32. Hero Group Title

$-1< \sin(\theta) < 1$ means that the value of sine can only be between - or + one. So there's no such thing as $$\sin(\theta) = 1.17$$