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 one year ago
will give medal to best answer!
The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used.
C = 38°, a = 19, c = 10
 one year ago
will give medal to best answer! The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used. C = 38°, a = 19, c = 10

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Hero
 one year ago
Best ResponseYou've already chosen the best response.1Did you try simply using Law of Sines to figure it out?

meg1334
 one year ago
Best ResponseYou've already chosen the best response.0yes but i didnt understand

Hero
 one year ago
Best ResponseYou've already chosen the best response.1What did you come up with?

meg1334
 one year ago
Best ResponseYou've already chosen the best response.0i got sin A = 67 but that isnt in my answer choices No triangle is formed. A = 58.6°, B = 83.4°, b ≈ 15.6 A = 83.4°, B = 58.6°, b ≈ 15.6 The triangle cannot be solved with the Law of Sines.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1I don't understand how you got that. Please show me the steps you took to get A = 67

meg1334
 one year ago
Best ResponseYou've already chosen the best response.0i used c/ sin c = a/ sin a 10/sin 37 = 19/sin a and then i divided 19 sin 38 over sin 10 and i got 67.36

Hero
 one year ago
Best ResponseYou've already chosen the best response.1where did you get the 37 from?

meg1334
 one year ago
Best ResponseYou've already chosen the best response.0I meant 38, i used 38 in my claculations and still got 67

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Are you in degree mode or radian mode?

meg1334
 one year ago
Best ResponseYou've already chosen the best response.0i dont know i just typed it in and got 67, cant you check it?

Hero
 one year ago
Best ResponseYou've already chosen the best response.1You must make sure you're in degree mode. That's very important.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1But either way it goes, you're not doing it correctly.

meg1334
 one year ago
Best ResponseYou've already chosen the best response.0oh really, i hadnt noticed that im doing it wrong. I need help thats why im on here obviously

Hero
 one year ago
Best ResponseYou've already chosen the best response.1\[\sin A = \frac{19\sin(38^{\circ})}{10} \\\sin A = \]

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Compute the right hand side again and let me know what you get. Make sure you're in degree mode.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Okay now \[\sin A = 1.169756803\] So how do we find A?

meg1334
 one year ago
Best ResponseYou've already chosen the best response.0a is 19, sin A is 1.16, what do you mean find A?

Hero
 one year ago
Best ResponseYou've already chosen the best response.1I'm not talking about a = 19. That's a side length

Hero
 one year ago
Best ResponseYou've already chosen the best response.1\[\sin (A^{\circ}) = 1.169756803\] I'm talking about Angle A. Find that.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1You take the inverse sine of both sides to get: \[\sin^{1}(A^{\circ}) = \sin^{1}({1.169756803}) \\A^{\circ} = \sin^{1}({1.169756803}) \]

Hero
 one year ago
Best ResponseYou've already chosen the best response.1So compute \[\sin^{1}({1.169756803})\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Let me know what you get.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1That's what it should say because no such angle exists.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1And if the angle doesn't exist, then the triangle can't possibly exist.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1\[1< \sin(\theta) < 1\] means that the value of sine can only be between  or + one. So there's no such thing as \(\sin(\theta) = 1.17\)
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