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Find the rate of change of the area of a circle per second with respect to
its radius r when r = 5 cm.
 one year ago
 one year ago
Find the rate of change of the area of a circle per second with respect to its radius r when r = 5 cm.
 one year ago
 one year ago

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ParthKohliBest ResponseYou've already chosen the best response.1
Differentiate \(\pi r^2\) with respect to \(r\).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
When you find \(f'(r)\), find \(f'(5)\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
The answer turns out to be the circumference.
 one year ago

BAdhiBest ResponseYou've already chosen the best response.0
Actually shouldn't it be like this, $$A=\pi r^2$$ Since rate of change is associated with 'time' differentiation with respect to 't' time, $$\frac{dA}{dt}=\pi\frac{dr^2}{dt}=2\pi r\frac{dr}{dt}$$ rate of change in radius should be given
 one year ago
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