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soty2013
Group Title
If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the
approximate error in calculating its volume.
 one year ago
 one year ago
soty2013 Group Title
If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.
 one year ago
 one year ago

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soty2013 Group TitleBest ResponseYou've already chosen the best response.0
@Yolo? @yololol
 one year ago

yololol Group TitleBest ResponseYou've already chosen the best response.0
Why would I help you?
 one year ago

Yolo? Group TitleBest ResponseYou've already chosen the best response.5
The answer is 6
 one year ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
you both look so sweet sid by side :) GOD Bless you...
 one year ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
Thanks @chad
 one year ago

yololol Group TitleBest ResponseYou've already chosen the best response.0
http://media.tumblr.com/tumblr_mdyb2b8jJu1rp7g3w.gif
 one year ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
is that you @becca ?
 one year ago

yololol Group TitleBest ResponseYou've already chosen the best response.0
It's not me in the Gif, no.
 one year ago

InYourHead Group TitleBest ResponseYou've already chosen the best response.2
The approximate error would actually be 12 cubic meters. ~~~~~~~ Here's the formula for finding the volume of a sphere: \[\frac{ 4 }{ 3 }\pi r^{3}\] That's "fourthirds, times pi, times the radius CUBED." (Not squared, even though the little 3 looks like a 2.) ~~~~~~~~~~~~~~ If we assume that the radius of the sphere is 7, then the volume would be 1432.44 cubic meters. But since the error is 0.02, the ACTUAL radius of the sphere could be 7.02, or 6.98. If we assume that the radius is 7.02, then the volume would be 1444.76 cubic meters. And if we assume that the radius is 6.98, then the volume would be 1420.20 cubic meters. ~~~~~~~~~~~~~ The difference between 1444.76 and 1432.44 is 12.32. And the difference between 1432.44 and 1420.20 is 12.24. So you see, the error is about 12.00 cubic meters, if we round it.
 one year ago

Yolo? Group TitleBest ResponseYou've already chosen the best response.5
Damn you just wasted all your time writing that lol
 one year ago

InYourHead Group TitleBest ResponseYou've already chosen the best response.2
Better than wasting my time on giving someone a wrong answer. Right?
 one year ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
@rebeccaskell94
 one year ago

Yolo? Group TitleBest ResponseYou've already chosen the best response.5
He didnt really want an answer lol he was just trying to troll me and Becca
 one year ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
@JamesJ
 one year ago

InYourHead Group TitleBest ResponseYou've already chosen the best response.2
@goformit100 "No"?
 one year ago

InYourHead Group TitleBest ResponseYou've already chosen the best response.2
Depending on whether I choose to multiply pi with 1.33, or to multiply pi with 1.33333, my spherical volume could be off by anywhere from 3 to 5 meters. But in the end, the error is still about 12 cubic meters.
 one year ago
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