anonymous
  • anonymous
If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Yolo? @yololol
anonymous
  • anonymous
Why would I help you?
anonymous
  • anonymous
The answer is 6

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anonymous
  • anonymous
you both look so sweet sid by side :) GOD Bless you...
anonymous
  • anonymous
Bye...
anonymous
  • anonymous
Thanks @chad
anonymous
  • anonymous
http://media.tumblr.com/tumblr_mdyb2b8jJu1rp7g3w.gif
anonymous
  • anonymous
is that you @becca ?
anonymous
  • anonymous
It's not me in the Gif, no.
anonymous
  • anonymous
lol
anonymous
  • anonymous
The approximate error would actually be 12 cubic meters. ~~~~~~~ Here's the formula for finding the volume of a sphere: \[\frac{ 4 }{ 3 }\pi r^{3}\] That's "four-thirds, times pi, times the radius CUBED." (Not squared, even though the little 3 looks like a 2.) ~~~~~~~~~~~~~~ If we assume that the radius of the sphere is 7, then the volume would be 1432.44 cubic meters. But since the error is 0.02, the ACTUAL radius of the sphere could be 7.02, or 6.98. If we assume that the radius is 7.02, then the volume would be 1444.76 cubic meters. And if we assume that the radius is 6.98, then the volume would be 1420.20 cubic meters. ~~~~~~~~~~~~~ The difference between 1444.76 and 1432.44 is 12.32. And the difference between 1432.44 and 1420.20 is 12.24. So you see, the error is about 12.00 cubic meters, if we round it.
anonymous
  • anonymous
Damn you just wasted all your time writing that lol
anonymous
  • anonymous
Better than wasting my time on giving someone a wrong answer. Right?
goformit100
  • goformit100
@rebeccaskell94
anonymous
  • anonymous
He didnt really want an answer lol he was just trying to troll me and Becca
goformit100
  • goformit100
No...
goformit100
  • goformit100
@JamesJ
anonymous
  • anonymous
@goformit100 "No"?
anonymous
  • anonymous
Depending on whether I choose to multiply pi with 1.33, or to multiply pi with 1.33333, my spherical volume could be off by anywhere from 3 to 5 meters. But in the end, the error is still about 12 cubic meters.

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