Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

Why would I help you?
The answer is 6

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

you both look so sweet sid by side :) GOD Bless you...
Bye...
Thanks @chad
http://media.tumblr.com/tumblr_mdyb2b8jJu1rp7g3w.gif
is that you @becca ?
It's not me in the Gif, no.
lol
The approximate error would actually be 12 cubic meters. ~~~~~~~ Here's the formula for finding the volume of a sphere: \[\frac{ 4 }{ 3 }\pi r^{3}\] That's "four-thirds, times pi, times the radius CUBED." (Not squared, even though the little 3 looks like a 2.) ~~~~~~~~~~~~~~ If we assume that the radius of the sphere is 7, then the volume would be 1432.44 cubic meters. But since the error is 0.02, the ACTUAL radius of the sphere could be 7.02, or 6.98. If we assume that the radius is 7.02, then the volume would be 1444.76 cubic meters. And if we assume that the radius is 6.98, then the volume would be 1420.20 cubic meters. ~~~~~~~~~~~~~ The difference between 1444.76 and 1432.44 is 12.32. And the difference between 1432.44 and 1420.20 is 12.24. So you see, the error is about 12.00 cubic meters, if we round it.
Damn you just wasted all your time writing that lol
Better than wasting my time on giving someone a wrong answer. Right?
He didnt really want an answer lol he was just trying to troll me and Becca
No...
Depending on whether I choose to multiply pi with 1.33, or to multiply pi with 1.33333, my spherical volume could be off by anywhere from 3 to 5 meters. But in the end, the error is still about 12 cubic meters.

Not the answer you are looking for?

Search for more explanations.

Ask your own question