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soty2013

  • one year ago

If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.

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  1. soty2013
    • one year ago
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    @Yolo? @yololol

  2. yololol
    • one year ago
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    Why would I help you?

  3. Yolo?
    • one year ago
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    The answer is 6

  4. soty2013
    • one year ago
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    you both look so sweet sid by side :) GOD Bless you...

  5. soty2013
    • one year ago
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    Bye...

  6. soty2013
    • one year ago
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    Thanks @chad

  7. yololol
    • one year ago
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    http://media.tumblr.com/tumblr_mdyb2b8jJu1rp7g3w.gif

  8. soty2013
    • one year ago
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    is that you @becca ?

  9. yololol
    • one year ago
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    It's not me in the Gif, no.

  10. soty2013
    • one year ago
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    lol

  11. InYourHead
    • one year ago
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    The approximate error would actually be 12 cubic meters. ~~~~~~~ Here's the formula for finding the volume of a sphere: \[\frac{ 4 }{ 3 }\pi r^{3}\] That's "four-thirds, times pi, times the radius CUBED." (Not squared, even though the little 3 looks like a 2.) ~~~~~~~~~~~~~~ If we assume that the radius of the sphere is 7, then the volume would be 1432.44 cubic meters. But since the error is 0.02, the ACTUAL radius of the sphere could be 7.02, or 6.98. If we assume that the radius is 7.02, then the volume would be 1444.76 cubic meters. And if we assume that the radius is 6.98, then the volume would be 1420.20 cubic meters. ~~~~~~~~~~~~~ The difference between 1444.76 and 1432.44 is 12.32. And the difference between 1432.44 and 1420.20 is 12.24. So you see, the error is about 12.00 cubic meters, if we round it.

  12. Yolo?
    • one year ago
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    Damn you just wasted all your time writing that lol

  13. InYourHead
    • one year ago
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    Better than wasting my time on giving someone a wrong answer. Right?

  14. goformit100
    • one year ago
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    @rebeccaskell94

  15. Yolo?
    • one year ago
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    He didnt really want an answer lol he was just trying to troll me and Becca

  16. goformit100
    • one year ago
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    No...

  17. goformit100
    • one year ago
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    @JamesJ

  18. InYourHead
    • one year ago
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    @goformit100 "No"?

  19. InYourHead
    • one year ago
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    Depending on whether I choose to multiply pi with 1.33, or to multiply pi with 1.33333, my spherical volume could be off by anywhere from 3 to 5 meters. But in the end, the error is still about 12 cubic meters.

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