Consider the functions f(x) = 3x(to the 2nd power) + 1 and g(x) = x + 3. What is the value of f[g(−1)]?
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i THINK you have to set it up like this: 3(x+3)^2+1
and if its g(-1) then you plug in -1 for x
which would get you 2
so it'd be 3(2)^2+1
which is 3(4)+1
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yeah im pretty sure its c
Thank you!! :D :D :D!
no problem (: i just had to think about it a little
Consider the functions f(x) = 2(x − 3) and g(x) = 3x. What is the value of (f + g)(3)?
give me a sec i have to work this out
ok first plug in 3 for the x values in f(x) = 2(x-3)
what do get?
lol you catch on quick and i didnt even have to explain the rest of it. GOOD JOB :D
no problem (:
Select the equations that are parallel and perpendicular to y = −3x − 1 and that pass through the point (3, 1).
A. parallel: y = −3x + 6
perpendicular: y = (1/3)x + 2(2/3)
B. parallel: y = −3x + 10
perpendicular: y = (1/3)x
C. parallel: y = -(1/3)x
perpendicular: y = −3x
D. parallel: y = (1/3)x + 1
perpendicular: y = 3x − 1
i dont know that one you're going to have to ask in a new question.
What about this?
Consider the functions f(x) = 2(x − 7) and g(x) = 2x. What is the value of (f − g)(4)?