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Find the probability of the following five-card poker hands from a 52-card deck. In poker, aces are either high or low. Two pair (2 cards of one value, 2 of another value).
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The probability of five-card poker hands for two pairs is 0.04753902. Probability describes the attitude of mind that asks the question whether a certain event will occur. It measures the confidence of a person in regards to an event occurring.
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So i did the problem again and got a different answer this time. I'm pretty sure this is the right way to do it!!
First, there are
52C5 = 52! / (47! 5!) = 2,598,960 different possible five-card poker hands.
There are 13 possible ranks for the three cards of a kind, and each case leaves 12 possible ranks for the pair.
There are 4 ways to select three cards of any rank (differing in which card is omitted).
There are 4C2 = 6 ways to select a pair of any rank.
So, the number of different full houses is
13 * 12 * 4 * 6 = 3,744
The probability is therefore
3,744/2,598,960 = 6/4,165 = about 1.44*10-3