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 one year ago
Medal and become Fan Rewarded Please Help me :D
Find the probability of the following fivecard poker hands from a 52card deck. In poker, aces are either high or low. Two pair (2 cards of one value, 2 of another value).
 one year ago
Medal and become Fan Rewarded Please Help me :D Find the probability of the following fivecard poker hands from a 52card deck. In poker, aces are either high or low. Two pair (2 cards of one value, 2 of another value).

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e.cociuba
 one year ago
Best ResponseYou've already chosen the best response.2The probability of fivecard poker hands for two pairs is 0.04753902. Probability describes the attitude of mind that asks the question whether a certain event will occur. It measures the confidence of a person in regards to an event occurring.

Needhelpp101
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359757267374:dw

LizzyLove<3
 one year ago
Best ResponseYou've already chosen the best response.0@e.cociuba how please explain cause i need help to...

Needhelpp101
 one year ago
Best ResponseYou've already chosen the best response.1Hey Lizzy do you go to Ashworth College online?

LizzyLove<3
 one year ago
Best ResponseYou've already chosen the best response.0i dont get what ur sayin e.cociuba

LizzyLove<3
 one year ago
Best ResponseYou've already chosen the best response.0no...i just need help with something like tht

e.cociuba
 one year ago
Best ResponseYou've already chosen the best response.2hold on @LizzyLove<3

Needhelpp101
 one year ago
Best ResponseYou've already chosen the best response.1@e.cociuba please explain to me too :D thx

e.cociuba
 one year ago
Best ResponseYou've already chosen the best response.2So i did the problem again and got a different answer this time. I'm pretty sure this is the right way to do it!! First, there are 52C5 = 52! / (47! 5!) = 2,598,960 different possible fivecard poker hands. There are 13 possible ranks for the three cards of a kind, and each case leaves 12 possible ranks for the pair. There are 4 ways to select three cards of any rank (differing in which card is omitted). There are 4C2 = 6 ways to select a pair of any rank. So, the number of different full houses is 13 * 12 * 4 * 6 = 3,744 The probability is therefore 3,744/2,598,960 = 6/4,165 = about 1.44*103
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