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How many different ways are there to choose 2 of 4 different colors?
 one year ago
 one year ago
How many different ways are there to choose 2 of 4 different colors?
 one year ago
 one year ago

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HorseCrazyGirlForeverBest ResponseYou've already chosen the best response.0
If you could explain as well, that would be great! :D
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
For your first pick, you can pick any of 4 colors, so that is going to be "4 times something" so far. That leaves 3 colors of which you can pick any of the three. So, you have "4 times 3" so far. Now, you in effect have "doublecounted" because the order doesn't matter. So, you have "4 times 3 divided by 2" for your answer. This is 4C2 which is 4!/(2! times 2!)
 one year ago

HorseCrazyGirlForeverBest ResponseYou've already chosen the best response.0
The answer is 6?
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
btw, "!" notation, the exclamation mark, is "factorial", which is a number times every successive integer under it until you get to 1. Yes, the answer is 6.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
The answer is 6 as long as it doesn't matter which of the 2 colors was chosen first. Then the answer would be 12.
 one year ago

HorseCrazyGirlForeverBest ResponseYou've already chosen the best response.0
Okay I see now! Thank you so much. You have helped a ton! :D
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
Good luck to you in all of your studies and thx for the recognition! @HorseCrazyGirlForever And you're welcome!
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
A good way to visualize that it is 6 and that there is no order to the picking is to imagine grabbing 2 at the same time blindly out of a bag.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
Sounded funny. Visualizing blindly.
 one year ago
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