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anonymous
 3 years ago
How many different ways are there to choose 2 of 4 different colors?
anonymous
 3 years ago
How many different ways are there to choose 2 of 4 different colors?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you could explain as well, that would be great! :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0For your first pick, you can pick any of 4 colors, so that is going to be "4 times something" so far. That leaves 3 colors of which you can pick any of the three. So, you have "4 times 3" so far. Now, you in effect have "doublecounted" because the order doesn't matter. So, you have "4 times 3 divided by 2" for your answer. This is 4C2 which is 4!/(2! times 2!)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0btw, "!" notation, the exclamation mark, is "factorial", which is a number times every successive integer under it until you get to 1. Yes, the answer is 6.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The answer is 6 as long as it doesn't matter which of the 2 colors was chosen first. Then the answer would be 12.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay I see now! Thank you so much. You have helped a ton! :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Good luck to you in all of your studies and thx for the recognition! @HorseCrazyGirlForever And you're welcome!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A good way to visualize that it is 6 and that there is no order to the picking is to imagine grabbing 2 at the same time blindly out of a bag.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sounded funny. Visualizing blindly.
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