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 one year ago
How many different ways are there to choose 2 of 4 different colors?
 one year ago
How many different ways are there to choose 2 of 4 different colors?

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HorseCrazyGirlForever
 one year ago
Best ResponseYou've already chosen the best response.0If you could explain as well, that would be great! :D

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1For your first pick, you can pick any of 4 colors, so that is going to be "4 times something" so far. That leaves 3 colors of which you can pick any of the three. So, you have "4 times 3" so far. Now, you in effect have "doublecounted" because the order doesn't matter. So, you have "4 times 3 divided by 2" for your answer. This is 4C2 which is 4!/(2! times 2!)

HorseCrazyGirlForever
 one year ago
Best ResponseYou've already chosen the best response.0The answer is 6?

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1btw, "!" notation, the exclamation mark, is "factorial", which is a number times every successive integer under it until you get to 1. Yes, the answer is 6.

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1The answer is 6 as long as it doesn't matter which of the 2 colors was chosen first. Then the answer would be 12.

HorseCrazyGirlForever
 one year ago
Best ResponseYou've already chosen the best response.0Okay I see now! Thank you so much. You have helped a ton! :D

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1Good luck to you in all of your studies and thx for the recognition! @HorseCrazyGirlForever And you're welcome!

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1A good way to visualize that it is 6 and that there is no order to the picking is to imagine grabbing 2 at the same time blindly out of a bag.

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1Sounded funny. Visualizing blindly.
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