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TeemoTheTerific

  • 3 years ago

(-ab)^3 * (-ab^2)^2/-a^5 b^3 ill rewrite it neater Help please

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  1. TeemoTheTerific
    • 3 years ago
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    |dw:1359769885253:dw|

  2. TeemoTheTerific
    • 3 years ago
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    i dont understand how to work it out when its -a^3 involved

  3. TeemoTheTerific
    • 3 years ago
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    but i know all my index laws pretty well

  4. TeemoTheTerific
    • 3 years ago
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    @jim_thompson5910 can you please help?

  5. yummydum
    • 3 years ago
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    simplify the numerators..multiply :)

  6. yummydum
    • 3 years ago
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    |dw:1359770089396:dw|

  7. TeemoTheTerific
    • 3 years ago
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    @poopsiedoodle

  8. TeemoTheTerific
    • 3 years ago
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    @timo86m

  9. poopsiedoodle
    • 3 years ago
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    What are the instructions for this problem?

  10. yummydum
    • 3 years ago
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    |dw:1359770156078:dw|

  11. poopsiedoodle
    • 3 years ago
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    nevermind, looks like yummydum has this one covered.

  12. TeemoTheTerific
    • 3 years ago
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    simplify

  13. TeemoTheTerific
    • 3 years ago
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    is that final answer?

  14. yummydum
    • 3 years ago
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    yes :)

  15. TeemoTheTerific
    • 3 years ago
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    answer in the book is b^4 without negative?

  16. yummydum
    • 3 years ago
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    oh yes sorry

  17. TeemoTheTerific
    • 3 years ago
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    how did it become postive with your working out?

  18. yummydum
    • 3 years ago
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    -a^3 times -a^2 is -a^5 sprry

  19. yummydum
    • 3 years ago
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    sorry*

  20. yummydum
    • 3 years ago
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    |dw:1359770406091:dw|

  21. TeemoTheTerific
    • 3 years ago
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    thanks

  22. yummydum
    • 3 years ago
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    sorry for the confusion, yw

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