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DLS

  • 3 years ago

What will be the vertex of parabola y^2=12x?

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  1. DLS
    • 3 years ago
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    Focus is (3,0) and length of LR=12 but what would be the vertex?

  2. abb0t
    • 3 years ago
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    Its standard form: \[(y-k)^2=4p(x-h)\] where (h,k) = (x,y) coordinates of the vertex. Vertex(0,0)

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