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Find the current I as a function of time for the circuit in the following figure if the switch S is closed and I=0 at t=0, where E=5 volt(s), L=2 henry(s) and R=2 ohm(s).
 one year ago
 one year ago
Find the current I as a function of time for the circuit in the following figure if the switch S is closed and I=0 at t=0, where E=5 volt(s), L=2 henry(s) and R=2 ohm(s).
 one year ago
 one year ago

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MashyBest ResponseYou've already chosen the best response.0
Is this an AC circuit or a DC circuit?.. cause if the supply is DC then inductor doesn't play a role! :/
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
When the switch is closed the battery tries to drive a current of value E/R through the circuit, but owing to the inductance L the current is initially zero and slowly builds up to this value. It is necessary to form and solve a differential equation to find the current as a function of time. This can be found in textbooks and the solution is: \[i=\frac{E}{R}(1e ^{\frac{Rt}{L}})\]
 one year ago

MashyBest ResponseYou've already chosen the best response.0
oh this is the transient stage current right?
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
@Mashy It is better described as initial growth of current (starting from zero current due to the back emf of the inductance).
 one year ago

MashyBest ResponseYou've already chosen the best response.0
yea.. so thats what we call as transient stage in the electronics where the current is just growing.. once it reaches a steady value, no longer will inductor contribute.. and so we call that as a steady state right? :)
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
@Mashy Yes, the steady state current is E/R.
 one year ago
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