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 one year ago
A fair die is rolled (2n+1) times.The probability that the faces with even number show odd number of times is
a) (3n+1)/(4n+2) b) 3/4
c)2/3 d)1/2
 one year ago
A fair die is rolled (2n+1) times.The probability that the faces with even number show odd number of times is a) (3n+1)/(4n+2) b) 3/4 c)2/3 d)1/2

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wio
 one year ago
Best ResponseYou've already chosen the best response.1The whole roll 2n+1 times, get k even numbered die is a binomial distribution but I wonder

wio
 one year ago
Best ResponseYou've already chosen the best response.1if the symmetry of the probability can't make this a bit easier.

wio
 one year ago
Best ResponseYou've already chosen the best response.1We can definitely use the fact that it is multiple choice though...

wio
 one year ago
Best ResponseYou've already chosen the best response.1If \(n=0\) then clearly getting an even face means you win, so the probability is \(1/2\).

sritama
 one year ago
Best ResponseYou've already chosen the best response.0i am getting d as the answer , but the book is saying a.

wio
 one year ago
Best ResponseYou've already chosen the best response.1When \(n=1\). what is the probability?

wio
 one year ago
Best ResponseYou've already chosen the best response.1You have three rolls, if you roll 1 or 3 evens, you win

wio
 one year ago
Best ResponseYou've already chosen the best response.1oops, that doesn't actually matter, when \(n=1\) then a) is still 1/2

wio
 one year ago
Best ResponseYou've already chosen the best response.1They need to be different.

wio
 one year ago
Best ResponseYou've already chosen the best response.1n=2 gives 7/10 for a, but d is still 1/2 so.... 5 rolls, what is the probability of odd even rolls

wio
 one year ago
Best ResponseYou've already chosen the best response.1Weird... There is no explanation for a)?
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