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anonymous
 3 years ago
A fair die is rolled (2n+1) times.The probability that the faces with even number show odd number of times is
a) (3n+1)/(4n+2) b) 3/4
c)2/3 d)1/2
anonymous
 3 years ago
A fair die is rolled (2n+1) times.The probability that the faces with even number show odd number of times is a) (3n+1)/(4n+2) b) 3/4 c)2/3 d)1/2

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The whole roll 2n+1 times, get k even numbered die is a binomial distribution but I wonder

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if the symmetry of the probability can't make this a bit easier.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0We can definitely use the fact that it is multiple choice though...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If \(n=0\) then clearly getting an even face means you win, so the probability is \(1/2\).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Which knocks out b and c

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am getting d as the answer , but the book is saying a.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0When \(n=1\). what is the probability?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You have three rolls, if you roll 1 or 3 evens, you win

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oops, that doesn't actually matter, when \(n=1\) then a) is still 1/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0They need to be different.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0n=2 gives 7/10 for a, but d is still 1/2 so.... 5 rolls, what is the probability of odd even rolls

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Weird... There is no explanation for a)?
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