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CalculatorBest ResponseYou've already chosen the best response.0
\[\Huge \sqrt{\frac{1x}{1+x}}\]
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
i get \[1x+\frac{x^2}{2}  \frac{x^3}{8}  \frac{3x^4}{64}\]
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
wolfram got \[\frac{3 x^5}{8}+\frac{3 x^4}{8}\frac{x^3}{2}+\frac{x^2}{2}x+1\]
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.0
Unfortunately i forgot the formula! D:
 one year ago

wioBest ResponseYou've already chosen the best response.1
I want to know what is meant by Expand, since that's the only thing that comes to mind.
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
you can use this \[(x+a)^n=\sum ^{n}_{ k=0} \left(\begin{matrix}n \\ k\end{matrix}\right) x^k a^{(nk)}\]
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
or \[(1+x)^n = 1+nx+\frac{(n)(n1)}{2!}(x^2)+...\]
 one year ago

wioBest ResponseYou've already chosen the best response.1
That works for \(n\in \mathbb{N}\).
 one year ago

wioBest ResponseYou've already chosen the best response.1
In this case you have a square root...
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
\[\sqrt{\frac{1x}{1+x}} \\ \\ \frac{\sqrt{1x}}{\sqrt{1+x}} \\ \\ (1x)^\frac{1}{2}(1+x)^{\frac{1}{2}}\]
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
mix them by multiplying together
 one year ago

wioBest ResponseYou've already chosen the best response.1
Yeah, my problem is with \(1/2 \notin \mathbb{N}\)
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
I don't think it should be natural number
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
i mean real number will do
 one year ago

wioBest ResponseYou've already chosen the best response.1
How can you have summations or binomial coefficients with rational numbers?
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
the formula list says can use
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
we use the second one (1+x)^n
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/Binomial_series look at the History section
 one year ago

amoodaryaBest ResponseYou've already chosen the best response.0
dw:1359798673882:dw
 one year ago

amoodaryaBest ResponseYou've already chosen the best response.0
dw:1359798819059:dw
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
or maybe its \[\frac{3 x^5}{8}+\frac{3 x^4}{8}\frac{x^3}{2}+\frac{x^2}{2}x+1\]
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
based from the formula as long as its in the from ("1"+x)^n should be fine to expand, i tried it
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
from \[(1x)^{1/2} \\ \\ n=1/2, x=x(for formula) \\ \\ [1\frac{x}{2}+\frac{(\frac{1}{2})(\frac{1}{2}1)}{2}(x^2)] \\ \\ 1\frac{x}{2}\frac{x^2}{8}\]
 one year ago
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