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\[\Huge \sqrt{\frac{1x}{1+x}}\]
 one year ago

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up to power x^2
 one year ago

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i get \[1x+\frac{x^2}{2}  \frac{x^3}{8}  \frac{3x^4}{64}\]
 one year ago

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@saifoo.khan
 one year ago

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wolfram got \[\frac{3 x^5}{8}+\frac{3 x^4}{8}\frac{x^3}{2}+\frac{x^2}{2}x+1\]
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
Unfortunately i forgot the formula! D:
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Is it a maclaurin series?
 one year ago

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you can try that
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
I want to know what is meant by Expand, since that's the only thing that comes to mind.
 one year ago

Calculator Group TitleBest ResponseYou've already chosen the best response.0
you can use this \[(x+a)^n=\sum ^{n}_{ k=0} \left(\begin{matrix}n \\ k\end{matrix}\right) x^k a^{(nk)}\]
 one year ago

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or \[(1+x)^n = 1+nx+\frac{(n)(n1)}{2!}(x^2)+...\]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
That works for \(n\in \mathbb{N}\).
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
In this case you have a square root...
 one year ago

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still can, watch
 one year ago

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\[\sqrt{\frac{1x}{1+x}} \\ \\ \frac{\sqrt{1x}}{\sqrt{1+x}} \\ \\ (1x)^\frac{1}{2}(1+x)^{\frac{1}{2}}\]
 one year ago

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expand separately
 one year ago

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mix them by multiplying together
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Yeah, my problem is with \(1/2 \notin \mathbb{N}\)
 one year ago

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I don't think it should be natural number
 one year ago

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i mean real number will do
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
How can you have summations or binomial coefficients with rational numbers?
 one year ago

amoodarya Group TitleBest ResponseYou've already chosen the best response.0
interval of x is ?
 one year ago

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the formula list says can use
 one year ago

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we use the second one (1+x)^n
 one year ago

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http://en.wikipedia.org/wiki/Binomial_series look at the History section
 one year ago

amoodarya Group TitleBest ResponseYou've already chosen the best response.0
dw:1359798673882:dw
 one year ago

amoodarya Group TitleBest ResponseYou've already chosen the best response.0
dw:1359798819059:dw
 one year ago

Calculator Group TitleBest ResponseYou've already chosen the best response.0
or maybe its \[\frac{3 x^5}{8}+\frac{3 x^4}{8}\frac{x^3}{2}+\frac{x^2}{2}x+1\]
 one year ago

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based from the formula as long as its in the from ("1"+x)^n should be fine to expand, i tried it
 one year ago

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from \[(1x)^{1/2} \\ \\ n=1/2, x=x(for formula) \\ \\ [1\frac{x}{2}+\frac{(\frac{1}{2})(\frac{1}{2}1)}{2}(x^2)] \\ \\ 1\frac{x}{2}\frac{x^2}{8}\]
 one year ago
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