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rmalik2

  • 3 years ago

a METAL cube has a edge length of 11.4 mm and retriceof 667g. Calulate the density of metal...Please help I believe the answer is 148.cm^3....

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  1. UnkleRhaukus
    • 3 years ago
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    the Volume of cube is \[V=s^3\] density is \[\rho=\frac mV\]

  2. rmalik2
    • 3 years ago
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    yes but I need help find volume...ive gotten 1481544mm^3 but needs to convert to cm^3

  3. rmalik2
    • 3 years ago
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    1481.544

  4. UnkleRhaukus
    • 3 years ago
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    to convert millimeters to centimeters \[1[\text{cm}]=10[\text{mm}]\] so \[1[\text{cm}]^3=(10[\text{mm}])^3=1000[\text{mm}]^3\]

  5. rmalik2
    • 3 years ago
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    yes but I understand it I keep getten the answer wrong..can you please show me the procedure?

  6. rmalik2
    • 3 years ago
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    the answer is 4.51g/cm^3 right??

  7. UnkleRhaukus
    • 3 years ago
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    \[\rho=\frac m{s^3}=\frac{667[\text g]}{{(11.4[\text{mm}])^3}}\]\[=\frac{667[\text g]}{1481.544[\text{mm}]^3}\]\[=\frac{667[\text g]}{1.481544[\text{cm}]^3}\]\[\approx 0.4502\tfrac{[\text g]}{[\text{cm}]^3}\]

  8. rmalik2
    • 3 years ago
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    thanks

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