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anonymous
 3 years ago
Calculate the volume of the solid, bounded by surfaces: z=x^2+y^2; z= 4x^2+4y^2;z=4
anonymous
 3 years ago
Calculate the volume of the solid, bounded by surfaces: z=x^2+y^2; z= 4x^2+4y^2;z=4

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0first take 4 common frm 2nd eq then subtract both equation x n y will b canceled n z will be = to 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then by comparin method find the value of x n put it in any of equ then y will automatically come

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay. Let's say I got the value of x, y and z. How will I calculate the volume? I am a bit rusty on triple integrals.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm thts pity difficult :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0multiply all the values didnt u get it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well the process I saw online was very difficult and it required a lot more effort. Just multiplication won't help.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohky m sorry i dnt knw more then that m student of 1st year so0o m sorry :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's alright aliza. Thanks for the insight.:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ur welcome nw m going just pray 4 ma tomorrows NSTC test leaving t,cr

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sure and don't worry you will do well.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2\pi}\int\limits_{1}^{2}\int\limits_{0}^{4}1 dV\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359821229243:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that would be the projection on the xy plane?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so now try elimination one of x/y and write it interms of z and the other var

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i mean y=root(zx**2)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359821411153:dw i hope u know how to find the area of the shaded part? i mean in 2d? extend it to 3d adding a dz

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0fine let's make a guess.............state ur options i m in no mood to solve it either

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dose are the options... what do u think wud be a good gess

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0consider two circles x**2 + y**2=4 and x**2+y**2=1 what would be the area b/n them?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0times 4 and we get 12pi

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nope now it's gone 3d multiply it with 4 #height ok? now it's 12 pi now approximate it to be a cone now wat's the volume of a cone?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0owwww i didnt think of that..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.04/3 * 12 * pi =8*pi ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now find the closest answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0noo sorry it's 1/3 * 12 *pi 4pi now wat's the closest?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0idk deres 2pi and 6pi and 8pi... i gess 2pi then

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup cone obviously has a larger volume :P guess that's it @shubhanknigam

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you both of you, Tushara and Avinash. You were a big help. Guess I can sleep now.
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