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shubhanknigam

  • one year ago

Calculate the volume of the solid, bounded by surfaces: z=x^2+y^2; z= 4x^2+4y^2;z=4

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  1. aliza.khan
    • one year ago
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    first take 4 common frm 2nd eq then subtract both equation x n y will b canceled n z will be = to 4

  2. shubhanknigam
    • one year ago
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    Okay.Then?

  3. aliza.khan
    • one year ago
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    then by comparin method find the value of x n put it in any of equ then y will automatically come

  4. shubhanknigam
    • one year ago
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    Okay. Let's say I got the value of x, y and z. How will I calculate the volume? I am a bit rusty on triple integrals.

  5. aliza.khan
    • one year ago
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    hmm thts pity difficult :P

  6. aliza.khan
    • one year ago
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    multiply all the values didnt u get it?

  7. shubhanknigam
    • one year ago
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    Well the process I saw online was very difficult and it required a lot more effort. Just multiplication won't help.

  8. aliza.khan
    • one year ago
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    ohky m sorry i dnt knw more then that m student of 1st year so0o m sorry :(

  9. shubhanknigam
    • one year ago
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    It's alright aliza. Thanks for the insight.:)

  10. aliza.khan
    • one year ago
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    ur welcome nw m going just pray 4 ma tomorrows NSTC test leaving t,cr

  11. shubhanknigam
    • one year ago
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    Sure and don't worry you will do well.

  12. aliza.khan
    • one year ago
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    :) inshaallah

  13. shubhanknigam
    • one year ago
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    inshaallah.

  14. Tushara
    • one year ago
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    \[\int\limits_{0}^{2\pi}\int\limits_{1}^{2}\int\limits_{0}^{4}1 dV\]

  15. A.Avinash_Goutham
    • one year ago
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    |dw:1359821229243:dw|

  16. A.Avinash_Goutham
    • one year ago
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    that would be the projection on the x-y plane?

  17. shubhanknigam
    • one year ago
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    Okay.

  18. A.Avinash_Goutham
    • one year ago
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    so now try elimination one of x/y and write it interms of z and the other var

  19. A.Avinash_Goutham
    • one year ago
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    i mean y=root(z-x**2)

  20. A.Avinash_Goutham
    • one year ago
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    |dw:1359821411153:dw| i hope u know how to find the area of the shaded part? i mean in 2-d? extend it to 3-d adding a dz

  21. A.Avinash_Goutham
    • one year ago
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    fine let's make a guess.............state ur options i m in no mood to solve it either

  22. Tushara
    • one year ago
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    2pi,8pi,6pi and 35/4

  23. Tushara
    • one year ago
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    dose are the options... what do u think wud be a good gess

  24. A.Avinash_Goutham
    • one year ago
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    consider two circles x**2 + y**2=4 and x**2+y**2=1 what would be the area b/n them?

  25. Tushara
    • one year ago
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    radius:2 and 1

  26. A.Avinash_Goutham
    • one year ago
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    4pi-pi? 3pi?

  27. Tushara
    • one year ago
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    so area=3

  28. Tushara
    • one year ago
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    times 4 and we get 12pi

  29. A.Avinash_Goutham
    • one year ago
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    nope now it's gone 3d multiply it with 4 #height ok? now it's 12 pi now approximate it to be a cone now wat's the volume of a cone?

  30. Tushara
    • one year ago
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    owwww i didnt think of that..

  31. A.Avinash_Goutham
    • one year ago
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    4/3 * 12 * pi =8*pi ?

  32. Tushara
    • one year ago
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    1/3(pi)(r^2)(h)

  33. A.Avinash_Goutham
    • one year ago
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    now find the closest answer

  34. Tushara
    • one year ago
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    8pi

  35. A.Avinash_Goutham
    • one year ago
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    noo sorry it's 1/3 * 12 *pi 4pi now wat's the closest?

  36. Tushara
    • one year ago
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    idk deres 2pi and 6pi and 8pi... i gess 2pi then

  37. A.Avinash_Goutham
    • one year ago
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    yup cone obviously has a larger volume :P guess that's it @shubhanknigam

  38. shubhanknigam
    • one year ago
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    Thank you both of you, Tushara and Avinash. You were a big help. Guess I can sleep now.

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