Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
shubhanknigam
Group Title
Calculate the volume of the solid, bounded by surfaces: z=x^2+y^2; z= 4x^2+4y^2;z=4
 one year ago
 one year ago
shubhanknigam Group Title
Calculate the volume of the solid, bounded by surfaces: z=x^2+y^2; z= 4x^2+4y^2;z=4
 one year ago
 one year ago

This Question is Open

aliza.khan Group TitleBest ResponseYou've already chosen the best response.0
first take 4 common frm 2nd eq then subtract both equation x n y will b canceled n z will be = to 4
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
Okay.Then?
 one year ago

aliza.khan Group TitleBest ResponseYou've already chosen the best response.0
then by comparin method find the value of x n put it in any of equ then y will automatically come
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
Okay. Let's say I got the value of x, y and z. How will I calculate the volume? I am a bit rusty on triple integrals.
 one year ago

aliza.khan Group TitleBest ResponseYou've already chosen the best response.0
hmm thts pity difficult :P
 one year ago

aliza.khan Group TitleBest ResponseYou've already chosen the best response.0
multiply all the values didnt u get it?
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
Well the process I saw online was very difficult and it required a lot more effort. Just multiplication won't help.
 one year ago

aliza.khan Group TitleBest ResponseYou've already chosen the best response.0
ohky m sorry i dnt knw more then that m student of 1st year so0o m sorry :(
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
It's alright aliza. Thanks for the insight.:)
 one year ago

aliza.khan Group TitleBest ResponseYou've already chosen the best response.0
ur welcome nw m going just pray 4 ma tomorrows NSTC test leaving t,cr
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
Sure and don't worry you will do well.
 one year ago

aliza.khan Group TitleBest ResponseYou've already chosen the best response.0
:) inshaallah
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
inshaallah.
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{2\pi}\int\limits_{1}^{2}\int\limits_{0}^{4}1 dV\]
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
dw:1359821229243:dw
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
that would be the projection on the xy plane?
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
Okay.
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
so now try elimination one of x/y and write it interms of z and the other var
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
i mean y=root(zx**2)
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
dw:1359821411153:dw i hope u know how to find the area of the shaded part? i mean in 2d? extend it to 3d adding a dz
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
fine let's make a guess.............state ur options i m in no mood to solve it either
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
2pi,8pi,6pi and 35/4
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
dose are the options... what do u think wud be a good gess
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
consider two circles x**2 + y**2=4 and x**2+y**2=1 what would be the area b/n them?
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
radius:2 and 1
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
4pipi? 3pi?
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
times 4 and we get 12pi
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
nope now it's gone 3d multiply it with 4 #height ok? now it's 12 pi now approximate it to be a cone now wat's the volume of a cone?
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
owwww i didnt think of that..
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
4/3 * 12 * pi =8*pi ?
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
1/3(pi)(r^2)(h)
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
now find the closest answer
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
noo sorry it's 1/3 * 12 *pi 4pi now wat's the closest?
 one year ago

Tushara Group TitleBest ResponseYou've already chosen the best response.1
idk deres 2pi and 6pi and 8pi... i gess 2pi then
 one year ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.1
yup cone obviously has a larger volume :P guess that's it @shubhanknigam
 one year ago

shubhanknigam Group TitleBest ResponseYou've already chosen the best response.0
Thank you both of you, Tushara and Avinash. You were a big help. Guess I can sleep now.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.