I'm having trouble solving this differential equation
(1 - x^2) y' - xy = x
I'm not sure about the integrating factor
is it (1 - x^2) ^(1/2) or 1/ ((1 - x^2)^(1/2)
(or maybe its neither!). Please help.

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if in the form
y' + P(x) y = Q(x)
the integrating factor is e^F
where F= integral P(x) dx

\[(1-x^2)\frac{dy}{dx} -xy = x\]

@ph1 - yes - I remembered that I'm (to my shame) confuse by the algebra

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