leenajain.1996
Solve Trigonometric equation: sinx +cosx +sin2x=1/2.............reply fast....



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SmartWish
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sin2x can be rewritten

leenajain.1996
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ya as 2sinxcosx but what next?

shubhamsrg
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2sinx + 2cos x + 4sinx cosx = 1
2sinx( 1 + 2cosx) + 2cosx = 1
2sinx(1+ 2cosx) + (1+2 cosx) =2
(1+ 2sinx)(1+2cosx) = 2

shubhamsrg
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I don't have much idea next, leme see

leenajain.1996
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yes thanks a lot thats absolutely fine! i got an idea to solve the question

shubhamsrg
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Will you share that idea ?

leenajain.1996
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2sinx=1; 2cosx=1 and further by the formulae sin theta =sin alpha and so on....

shubhamsrg
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sinx and cosx both can not be 1/2 for the same value of x, you're logic is flawed.

shubhamsrg
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Its quite complicated to solve this, are you sure you have the right ques ?

leenajain.1996
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i know there may be some problem in the question or the expansion....wait..question is cosx+sinxsin2x=1/2 so in that way it can be solved

shubhamsrg
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sin2x !!

shubhamsrg
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its easily solvable then

shubhamsrg
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2cosx + 2sinx  4sinx cosx = 1
2sinx(1  2cosx) = (12cosx)
=>(2sinx)(1 2cosx) =0
BAZINGA !

leenajain.1996
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wow!!! thanks....i was a bit confused....thanks a lot!

shubhamsrg
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Glad to have helped.

shubhamsrg
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Correction :

shubhamsrg
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it'll be
(12sinx)(1 2cosx) =0

leenajain.1996
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ya i got that....k thanks bye gtg