anonymous
  • anonymous
Solve Trigonometric equation:- sinx +cosx +sin2x=1/2.............reply fast....
Trigonometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
sin2x can be rewritten
anonymous
  • anonymous
ya as 2sinxcosx but what next?
shubhamsrg
  • shubhamsrg
2sinx + 2cos x + 4sinx cosx = 1 2sinx( 1 + 2cosx) + 2cosx = 1 2sinx(1+ 2cosx) + (1+2 cosx) =2 (1+ 2sinx)(1+2cosx) = 2

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shubhamsrg
  • shubhamsrg
I don't have much idea next, leme see
anonymous
  • anonymous
yes thanks a lot thats absolutely fine! i got an idea to solve the question
shubhamsrg
  • shubhamsrg
Will you share that idea ?
anonymous
  • anonymous
2sinx=1; 2cosx=1 and further by the formulae sin theta =sin alpha and so on....
shubhamsrg
  • shubhamsrg
sinx and cosx both can not be 1/2 for the same value of x, you're logic is flawed.
shubhamsrg
  • shubhamsrg
Its quite complicated to solve this, are you sure you have the right ques ?
anonymous
  • anonymous
i know there may be some problem in the question or the expansion....wait..question is cosx+sinx-sin2x=1/2 so in that way it can be solved
shubhamsrg
  • shubhamsrg
-sin2x !!
shubhamsrg
  • shubhamsrg
its easily solvable then
shubhamsrg
  • shubhamsrg
2cosx + 2sinx - 4sinx cosx = 1 2sinx(1 - 2cosx) = (1-2cosx) =>(2sinx)(1- 2cosx) =0 BAZINGA !
anonymous
  • anonymous
wow!!! thanks....i was a bit confused....thanks a lot!
shubhamsrg
  • shubhamsrg
Glad to have helped.
shubhamsrg
  • shubhamsrg
Correction :
shubhamsrg
  • shubhamsrg
it'll be (1-2sinx)(1- 2cosx) =0
anonymous
  • anonymous
ya i got that....k thanks bye gtg

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