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leenajain.1996

  • 2 years ago

Solve Trigonometric equation:- sinx +cosx +sin2x=1/2.............reply fast....

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  1. SmartWish
    • 2 years ago
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    sin2x can be rewritten

  2. leenajain.1996
    • 2 years ago
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    ya as 2sinxcosx but what next?

  3. shubhamsrg
    • 2 years ago
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    2sinx + 2cos x + 4sinx cosx = 1 2sinx( 1 + 2cosx) + 2cosx = 1 2sinx(1+ 2cosx) + (1+2 cosx) =2 (1+ 2sinx)(1+2cosx) = 2

  4. shubhamsrg
    • 2 years ago
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    I don't have much idea next, leme see

  5. leenajain.1996
    • 2 years ago
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    yes thanks a lot thats absolutely fine! i got an idea to solve the question

  6. shubhamsrg
    • 2 years ago
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    Will you share that idea ?

  7. leenajain.1996
    • 2 years ago
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    2sinx=1; 2cosx=1 and further by the formulae sin theta =sin alpha and so on....

  8. shubhamsrg
    • 2 years ago
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    sinx and cosx both can not be 1/2 for the same value of x, you're logic is flawed.

  9. shubhamsrg
    • 2 years ago
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    Its quite complicated to solve this, are you sure you have the right ques ?

  10. leenajain.1996
    • 2 years ago
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    i know there may be some problem in the question or the expansion....wait..question is cosx+sinx-sin2x=1/2 so in that way it can be solved

  11. shubhamsrg
    • 2 years ago
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    -sin2x !!

  12. shubhamsrg
    • 2 years ago
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    its easily solvable then

  13. shubhamsrg
    • 2 years ago
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    2cosx + 2sinx - 4sinx cosx = 1 2sinx(1 - 2cosx) = (1-2cosx) =>(2sinx)(1- 2cosx) =0 BAZINGA !

  14. leenajain.1996
    • 2 years ago
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    wow!!! thanks....i was a bit confused....thanks a lot!

  15. shubhamsrg
    • 2 years ago
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    Glad to have helped.

  16. shubhamsrg
    • 2 years ago
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    Correction :

  17. shubhamsrg
    • 2 years ago
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    it'll be (1-2sinx)(1- 2cosx) =0

  18. leenajain.1996
    • 2 years ago
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    ya i got that....k thanks bye gtg

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