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leenajain.1996

Solve Trigonometric equation:- sinx +cosx +sin2x=1/2.............reply fast....

  • one year ago
  • one year ago

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  1. SmartWish
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    sin2x can be rewritten

    • one year ago
  2. leenajain.1996
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    ya as 2sinxcosx but what next?

    • one year ago
  3. shubhamsrg
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    2sinx + 2cos x + 4sinx cosx = 1 2sinx( 1 + 2cosx) + 2cosx = 1 2sinx(1+ 2cosx) + (1+2 cosx) =2 (1+ 2sinx)(1+2cosx) = 2

    • one year ago
  4. shubhamsrg
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    I don't have much idea next, leme see

    • one year ago
  5. leenajain.1996
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    yes thanks a lot thats absolutely fine! i got an idea to solve the question

    • one year ago
  6. shubhamsrg
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    Will you share that idea ?

    • one year ago
  7. leenajain.1996
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    2sinx=1; 2cosx=1 and further by the formulae sin theta =sin alpha and so on....

    • one year ago
  8. shubhamsrg
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    sinx and cosx both can not be 1/2 for the same value of x, you're logic is flawed.

    • one year ago
  9. shubhamsrg
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    Its quite complicated to solve this, are you sure you have the right ques ?

    • one year ago
  10. leenajain.1996
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    i know there may be some problem in the question or the expansion....wait..question is cosx+sinx-sin2x=1/2 so in that way it can be solved

    • one year ago
  11. shubhamsrg
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    -sin2x !!

    • one year ago
  12. shubhamsrg
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    its easily solvable then

    • one year ago
  13. shubhamsrg
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    2cosx + 2sinx - 4sinx cosx = 1 2sinx(1 - 2cosx) = (1-2cosx) =>(2sinx)(1- 2cosx) =0 BAZINGA !

    • one year ago
  14. leenajain.1996
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    wow!!! thanks....i was a bit confused....thanks a lot!

    • one year ago
  15. shubhamsrg
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    Glad to have helped.

    • one year ago
  16. shubhamsrg
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    Correction :

    • one year ago
  17. shubhamsrg
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    it'll be (1-2sinx)(1- 2cosx) =0

    • one year ago
  18. leenajain.1996
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    ya i got that....k thanks bye gtg

    • one year ago
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