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Try DeMorgan

what is bar ?

Does \(+\) mean \(\wedge\) and \(\bar{a}\) =\(\neg{a}\)

\[\overline{a}\] = complement of a

Okay, so \(\neg a\) indeed.

\[a + b + \bar{a} \iff a \wedge b \wedge \neg a\]It's zero . . .

The answer is 1 :|

So does \(+\) stand for the OR operator?

Yes.

then it is 1 indeed since either a or neg(a) is 1 :-)

What does \(ab\) mean? And?

Yes :|
Don't you write in this way?

You can write this both ways :-)

\[a\lor b\lor \neg a\iff a\lor b\lor\neg a\land\neg b\]
?

Yes, they're pretty much equivalent using truth tables.

I can't read (don't understand) all those symbols!! :(

Eh, it's easy once you are used to it.

Apparently we're not even caring about \(c\) in that expression.

truth table ?

If ∨ = OR
¬ = NOT
∧ = AND
Then, the way to get a∨b∨¬a⟺a∨b∨¬a∧¬b is what I want know :|

Well, manipulation. I thought you wanted a proof.

Dangy, that's just a truth table. I was waiting to see the manipulations @UnkleRhaukus does.

Because they have the same boolean values for each case.

is \(a\)= 1 , \(\bar a\)= 0 ?

Yes.

@UnkleRhaukus \(\neg\) lol

If a = 1, then \(\bar{a}\)=0.