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soumya007

  • 2 years ago

can anyone plz solve y'' - y = 8*e^-3*x ???? plz it is urgent ......

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  1. shubhamsrg
    • 2 years ago
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    e^(-3x) or (e^-3)*x Am assuming the former one ?

  2. soumya007
    • 2 years ago
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    the 1st one. and also the paricular solution is e^(-3*x)..

  3. shubhamsrg
    • 2 years ago
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    y= C e^(-3x) works right ? y' = -3C( e^-3x) y'' = 9C(e^-3x) => 9C(e^(-3x)) - C(e^-3x) = 8(e^(-3x)) C=1 so y=e^(-3x) is a solution.

  4. soumya007
    • 2 years ago
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    what about the value of C ??????? can it be any cosnt or somthing else ?

  5. shubhamsrg
    • 2 years ago
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    We just solved it, C=1

  6. shubhamsrg
    • 2 years ago
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    infact, Ae^x + Ce^(-3x) can also be a soltuion.

  7. shubhamsrg
    • 2 years ago
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    where C=1 and A can be anything

  8. soumya007
    • 2 years ago
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    thnak u....

  9. shubhamsrg
    • 2 years ago
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    I am pretty sure there might be more solutions to it. Nevermind

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