Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
i thinkof a no & add 12 then i start again with the no double it & subtract 8 .the two results are same. can someone help
 one year ago
 one year ago
i thinkof a no & add 12 then i start again with the no double it & subtract 8 .the two results are same. can someone help
 one year ago
 one year ago

This Question is Open

azolotorBest ResponseYou've already chosen the best response.1
add eight over and subtract x \[4=x\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Another way:\[x  4 = 2(x  4)\]So obviously, \(x  4 = 0\).
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
Or, x= +inf or inf! ;)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I hope any one of you didn't think of dividing both sides by \(x  4\), or you could have been jailed . . .
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Oh, new question?\[x + 12 = 2x  8\]
 one year ago

ruhanbasitBest ResponseYou've already chosen the best response.0
thanks A lot to help me but please can u tell me how to solve it step by step i ll highly apperciate thanx & regards in advance
 one year ago

azolotorBest ResponseYou've already chosen the best response.1
So you want to isolate x. First step is to get like terms on the same side with each other. SO add 8 over and subtract so you get \[4=x\] in this case. It won't always isolate quite so easily there may be division/multiplication involved but the process involved is always the same. Combine like terms and then isolate x
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.