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toadytica305
Group Title
I need help with this log function...
2^2x +^x12=0
 one year ago
 one year ago
toadytica305 Group Title
I need help with this log function... 2^2x +^x12=0
 one year ago
 one year ago

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toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
[2^2x +2^x12=0\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
put 2^x = y i think you mean \[2^{2x} +2^x12=0\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
\[(2^{x})^2 +2^x12=0 \\ 2^x=y \implies y^2+y12=0\] can you solve this quadratic in y ?
 one year ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
Didn't think of doing it that way.. I'll try it now
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
ask if you get stuck anywhere..
 one year ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
I get 7/2 and 3...
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
y^2+y12=0 (y+4)(y3)=0 y=4,3 what you got 7/2 and 3 for ? x ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
did you get how y=4,3 ?
 one year ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
The answer is supposed to be ln3/ln2
 one year ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
Yes, that part i did.. and i plugged those Y's into X
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
\(2^x=3 \\ \ln 2^x=\ln 3 \\ x \ln 2 = \ln 3 \\ x= \ln3/ \ln 2\)
 one year ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
Just saw where I messed up.. I pugged the Y's into 2^x... Thanks!!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
welcome ^_^
 one year ago
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