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anonymous
 3 years ago
I need help with this log function...
2^2x +^x12=0
anonymous
 3 years ago
I need help with this log function... 2^2x +^x12=0

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2put 2^x = y i think you mean \[2^{2x} +2^x12=0\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2\[(2^{x})^2 +2^x12=0 \\ 2^x=y \implies y^2+y12=0\] can you solve this quadratic in y ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Didn't think of doing it that way.. I'll try it now

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2ask if you get stuck anywhere..

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2y^2+y12=0 (y+4)(y3)=0 y=4,3 what you got 7/2 and 3 for ? x ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2did you get how y=4,3 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The answer is supposed to be ln3/ln2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, that part i did.. and i plugged those Y's into X

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2\(2^x=3 \\ \ln 2^x=\ln 3 \\ x \ln 2 = \ln 3 \\ x= \ln3/ \ln 2\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just saw where I messed up.. I pugged the Y's into 2^x... Thanks!!
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