anonymous
  • anonymous
I need help with this log function... 2^2x +^x-12=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
[2^2x +2^x-12=0\]
hartnn
  • hartnn
put 2^x = y i think you mean \[2^{2x} +2^x-12=0\]
hartnn
  • hartnn
\[(2^{x})^2 +2^x-12=0 \\ 2^x=y \implies y^2+y-12=0\] can you solve this quadratic in y ?

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anonymous
  • anonymous
Didn't think of doing it that way.. I'll try it now
hartnn
  • hartnn
ask if you get stuck anywhere..
anonymous
  • anonymous
I get -7/2 and 3...
hartnn
  • hartnn
y^2+y-12=0 (y+4)(y-3)=0 y=-4,3 what you got -7/2 and 3 for ? x ?
anonymous
  • anonymous
Yup
hartnn
  • hartnn
did you get how y=-4,3 ?
anonymous
  • anonymous
The answer is supposed to be ln3/ln2
anonymous
  • anonymous
Yes, that part i did.. and i plugged those Y's into X
hartnn
  • hartnn
\(2^x=3 \\ \ln 2^x=\ln 3 \\ x \ln 2 = \ln 3 \\ x= \ln3/ \ln 2\)
anonymous
  • anonymous
Just saw where I messed up.. I pugged the Y's into 2^x... Thanks!!
hartnn
  • hartnn
welcome ^_^

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